🕷️ Crawler Inspector

URL Lookup

Direct Parameter Lookup

Raw Queries and Responses

1. Shard Calculation

Query:

Response:

Calculated Shard: 97 (from laksa159)

2. Crawled Status Check

Query:

curl -X POST \
  'http://laksa097.int.ahrefs:8124/' \
  -H 'Content-Type: text/plain' \
  -H 'X-ClickHouse-Database: crawler3' \
  -H 'Authorization: Basic YXBpOg==' \
  -d 'SELECT getAhrefsURLFromUnparsed(src_unparsed) AS found_url, ifNull(toUnixTimestamp(download_stamp), 0) AS crawl_time, ifNull(toUnixTimestamp(props_url_first_seen), 0) AS first_indexed_time, download_http_code AS http_code, src_unparsed AS src_unparsed, src_root_hash AS src_root_hash, history_drop_reason AS history_drop_reason, meta_title AS meta_title, meta_descriptions AS meta_descriptions, attrs_boilerpipe_text AS attrs_boilerpipe_text, attrs_markdown AS attrs_markdown, attrs_readable_markdown AS attrs_readable_markdown, meta_canonical AS meta_canonical FROM crawler3.page_info_local FINAL PREWHERE (src_root_hash, src_unparsed) IN ((getAhrefsRootHashFromUnparsed(getAhrefsUnparsedNoserviceFromURL(\'https://www.wyzant.com/resources/answers/895150/value-of-resistor\')), getAhrefsUnparsedNoserviceFromURL(\'https://www.wyzant.com/resources/answers/895150/value-of-resistor\'))) FORMAT JSONEachRow'

Response:

{"found_url":"https:\/\/www.wyzant.com\/resources\/answers\/895150\/value-of-resistor","crawl_time":1774808211,"first_indexed_time":1652106129,"http_code":200,"src_unparsed":"com,wyzant!www,\/resources\/answers\/895150\/value-of-resistor s443","src_root_hash":"5366992188759543297","history_drop_reason":null,"meta_title":"VALUE OF RESISTOR | Wyzant Ask An Expert","meta_descriptions":["VALUE OF RESISTOR"],"attrs_boilerpipe_text":"Given Data:\nTotal resistance= (R+8)Ω\nvoltage = 60V\nCurrent = 2.5 A\nWe know that\nV=IR\nPut the data in above relation\n60=2.5×(R+8)\n60\/2.5=R+8\n24 = R+8\nR=24-8\nR= 16Ω\nHence, the value of resistor R is 16Ω.\nIf you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.","attrs_markdown":"[![Wyzant](https:\/\/apps.wyzant.io\/learnable\/fora\/logos\/ask-an-expert-vertical-d778300cea72ebace78c006bb693af13cfb0e4495f0d64d36f977842f65d5871.png)](https:\/\/www.wyzant.com\/resources\/answers \"Tutors, Tutoring Services, and Homework Help\")\n\n[Log in](https:\/\/www.wyzant.com\/login) [Sign up](https:\/\/www.wyzant.com\/signup)\n\nFind A Tutor\n\n[Search For Tutors](https:\/\/www.wyzant.com\/match\/search \"Search For Tutors\")\n\n[Request A Tutor](https:\/\/www.wyzant.com\/emailtutor \"Request A Tutor\")\n\n[Online Tutoring](https:\/\/www.wyzant.com\/online\/student \"Online Tutoring\")\n\nHow It Works\n\n[For Students](https:\/\/www.wyzant.com\/howitworks\/students \"For Students\")\n\n[FAQ](https:\/\/support.wyzant.com\/hc\/en-us \"FAQ\")\n\n[What Customers Say](https:\/\/www.wyzant.com\/reviews\/studentreviewsofwyzant \"What Customers Say\")\n\nResources\n\n[Ask An Expert](https:\/\/www.wyzant.com\/resources\/answers \"Ask An Expert\")\n\n[Search Questions](https:\/\/www.wyzant.com\/resources\/answers\/search \"Search Questions\")\n\n[Ask a Question](https:\/\/www.wyzant.com\/resources\/answers\/ask \"Ask a Question\")\n\n[Wyzant Blog](https:\/\/blog.wyzant.com\/ \"Wyzant Blog\")\n\nStart Tutoring\n\n[Apply Now](https:\/\/www.wyzant.com\/tutorsignupstart \"Apply Now\")\n\n[About Tutors Jobs](https:\/\/www.wyzant.com\/tutorhome \"About Tutors Jobs\")\n\n[Find Tutoring Jobs](https:\/\/www.wyzant.com\/jobsearch \"Find Tutoring Jobs\")\n\n[How It Works For Tutors](https:\/\/www.wyzant.com\/howitworks\/tutors \"How It Works For Tutors\")\n\n[FAQ](https:\/\/support.wyzant.com\/hc\/en-us \"FAQ\")\n\nAbout Us\n\n[About Us](https:\/\/www.wyzant.com\/about \"About Us\")\n\n[Careers](https:\/\/www.wyzant.com\/about\/careers \"Careers\")\n\n[Contact Us](https:\/\/support.wyzant.com\/hc\/en-us\/articles\/115005841543 \"Contact Us\")\n\n[All Questions](https:\/\/www.wyzant.com\/resources\/answers)\n\n[Search for a Question](https:\/\/www.wyzant.com\/resources\/answers\/search)\n\n[Find an Online Tutor Now](https:\/\/www.wyzant.com\/match\/search)\n\n[Ask a Question for Free](https:\/\/www.wyzant.com\/resources\/answers\/new)\n\n[Login](https:\/\/www.wyzant.com\/login)\n\nWYZANT TUTORING\n\n[Log in](https:\/\/www.wyzant.com\/login \"Log in\")\n\n[Sign up](https:\/\/www.wyzant.com\/signup \"Sign up\")\n\nFind A Tutor\n\n[Search For Tutors](https:\/\/www.wyzant.com\/match\/search \"Search For Tutors\")\n\n[Request A Tutor](https:\/\/www.wyzant.com\/emailtutor \"Request A Tutor\")\n\n[Online Tutoring](https:\/\/www.wyzant.com\/online\/student \"Online Tutoring\")\n\nHow It Works\n\n[For Students](https:\/\/www.wyzant.com\/howitworks\/students \"For Students\")\n\n[FAQ](https:\/\/support.wyzant.com\/hc\/en-us \"FAQ\")\n\n[What Customers Say](https:\/\/www.wyzant.com\/reviews\/studentreviewsofwyzant \"What Customers Say\")\n\nResources\n\n[Ask An Expert](https:\/\/www.wyzant.com\/resources\/answers \"Ask An Expert\")\n\n[Search Questions](https:\/\/www.wyzant.com\/resources\/answers\/search \"Search Questions\")\n\n[Ask a Question](https:\/\/www.wyzant.com\/resources\/answers\/ask \"Ask a Question\")\n\n[Wyzant Blog](https:\/\/blog.wyzant.com\/ \"Wyzant Blog\")\n\nStart Tutoring\n\n[Apply Now](https:\/\/www.wyzant.com\/tutorsignupstart \"Apply Now\")\n\n[About Tutors Jobs](https:\/\/www.wyzant.com\/tutorhome \"About Tutors Jobs\")\n\n[Find Tutoring Jobs](https:\/\/www.wyzant.com\/jobsearch \"Find Tutoring Jobs\")\n\n[How It Works For Tutors](https:\/\/www.wyzant.com\/howitworks\/tutors \"How It Works For Tutors\")\n\n[FAQ](https:\/\/support.wyzant.com\/hc\/en-us \"FAQ\")\n\nAbout Us\n\n[About Us](https:\/\/www.wyzant.com\/about \"About Us\")\n\n[Careers](https:\/\/www.wyzant.com\/about\/careers \"Careers\")\n\n[Contact Us](https:\/\/support.wyzant.com\/hc\/en-us\/articles\/115005841543 \"Contact Us\")\n\nSubject\n\nZIP\n\n[Search](https:\/\/www.wyzant.com\/match)\n\n[![](https:\/\/apps.wyzant.io\/learnable\/images\/logos\/ask-an-expert-horizontal.png)](https:\/\/www.wyzant.com\/resources\/answers)\n\n[Search](https:\/\/www.wyzant.com\/resources\/answers\/search)   [Find an Online Tutor Now](https:\/\/www.wyzant.com\/match\/search)   [Ask](https:\/\/www.wyzant.com\/resources\/answers\/ask)\n\n[Ask a Question For Free](https:\/\/www.wyzant.com\/resources\/answers\/ask)\n\n[Login](https:\/\/www.wyzant.com\/login)\n\n[Physics](https:\/\/www.wyzant.com\/resources\/answers\/topics\/physics) [Electrical Engineering](https:\/\/www.wyzant.com\/resources\/answers\/topics\/electrical-engineering)\n\nLorde L.\n\nasked  05\/09\/22\n# VALUE OF RESISTOR\nA resistor R in series with an 8 ohms resistor is connected across a 60 V voltage source delivering 2.5 A of current. What is the value of resistor R ?\n\n[Follow  1](https:\/\/www.wyzant.com\/resources\/answers\/895150\/toggle-follow)\n\n[Add comment](https:\/\/www.wyzant.com\/resources\/answers\/895150\/value-of-resistor#new-comment)\n\nMore\n\n[Report](https:\/\/www.wyzant.com\/resources\/answers\/895150\/report-reason)\n\n## 2 Answers By Expert Tutors\nBy:\n\n![]()\n\nSadia S. answered  05\/09\/22\n\nTutor\n\n4 (29)\n\nPHD Maths and Physics Tutor, Teacher, and Lecturer\\!\n\n[See tutors like this](https:\/\/www.wyzant.com\/match)\n\n[See tutors like this](https:\/\/www.wyzant.com\/match)\n\nGiven Data:\n\nTotal resistance= (R+8)Ω\n\nvoltage = 60V\n\nCurrent = 2.5 A\n\nWe know that **V=IR**\n\nPut the data in above relation\n\n60=2.5×(R+8)\n\n60\/2.5=R+8\n\n24 = R+8\n\nR=24-8\n\nR= 16Ω\n\n**Hence, the value of resistor R is 16Ω.**\n\n**If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.**\n\n[Upvote ** 1](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640534\/upvote)   [Downvote](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640534\/downvote)\n\n[Add comment](https:\/\/www.wyzant.com\/resources\/answers\/895150\/value-of-resistor#new-comment)\n\nMore\n\n[Report](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640534\/report-reason)\n\n[![]()](https:\/\/www.wyzant.com\/Tutors\/CA\/Sacramento\/9843762\/)\n\n[David C.](https:\/\/www.wyzant.com\/Tutors\/CA\/Sacramento\/9843762\/)  answered  05\/09\/22\n\nTutor\n\n4\\.4 (47)\n\n[Low Cost Math and Science Tutor](https:\/\/www.wyzant.com\/Tutors\/CA\/Sacramento\/9843762\/)\n\n[About this tutor ›](https:\/\/www.wyzant.com\/Tutors\/CA\/Sacramento\/9843762\/)\n\n[About this tutor ›](https:\/\/www.wyzant.com\/Tutors\/CA\/Sacramento\/9843762\/)\n\nTotal resistance = (8 + R) ohms = 60 V \/ 2.5 A = 24 ohms, so 8 + R = 24 ohms, so R = 16 ohms.\n\n[Upvote ** 1](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640532\/upvote)   [Downvote](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640532\/downvote)\n\n[Comment  1](https:\/\/www.wyzant.com\/resources\/answers\/895150\/value-of-resistor#edit-comment)\n\nMore\n\n[Report](https:\/\/www.wyzant.com\/resources\/answers\/895150\/answers\/640532\/report-reason)\n\nLorde L.\n\nThank you so much for your time, Sir\\!\n\n[Report](https:\/\/www.wyzant.com\/resources\/comments\/180789\/report-reason)\n\n05\/09\/22\n\n## Still looking for help? Get the right answer, fast.\n[Ask a question for free](https:\/\/www.wyzant.com\/resources\/answers\/ask)\n\nGet a free answer to a quick problem.  \n Most questions answered within 4 hours.\n#### OR\n[Find an Online Tutor Now](https:\/\/www.wyzant.com\/match)\n\nChoose an expert and meet online. No packages or subscriptions, pay only for the time you 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Reserved","attrs_readable_markdown":"Given Data:\n\nTotal resistance= (R+8)Ω\n\nvoltage = 60V\n\nCurrent = 2.5 A\n\nWe know that **V=IR**\n\nPut the data in above relation\n\n60=2.5×(R+8)\n\n60\/2.5=R+8\n\n24 = R+8\n\nR=24-8\n\nR= 16Ω\n\n**Hence, the value of resistor R is 16Ω.**\n\n**If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.**","meta_canonical":null}

3. Robots.txt Check

Query:

Response:

4. Spam/Ban Check

Query:

Response:

5. Seen Status Check

ℹ️ Skipped - page is already crawled

📄

INDEXABLE

✅

CRAWLED

13 days ago

🤖

ROBOTS ALLOWED

Page Info Filters

Filter	Status	Condition	Details
HTTP status	PASS	`download_http_code = 200`	HTTP 200
Age cutoff	PASS	`download_stamp > now() - 6 MONTH`	0.5 months ago
History drop	PASS	`isNull(history_drop_reason)`	No drop reason
Spam/ban	PASS	`fh_dont_index != 1 AND ml_spam_score = 0`	ml_spam_score=0
Canonical	PASS	`meta_canonical IS NULL OR = '' OR = src_unparsed`	Not set

Page Details

Property	Value
URL	https://www.wyzant.com/resources/answers/895150/value-of-resistor
Last Crawled	2026-03-29 18:16:51 (13 days ago)
First Indexed	2022-05-09 14:22:09 (3 years ago)
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Meta Title	VALUE OF RESISTOR \| Wyzant Ask An Expert
Meta Description	VALUE OF RESISTOR
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Boilerpipe Text	Given Data: Total resistance= (R+8)Ω voltage = 60V Current = 2.5 A We know that V=IR Put the data in above relation 60=2.5×(R+8) 60/2.5=R+8 24 = R+8 R=24-8 R= 16Ω Hence, the value of resistor R is 16Ω. If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.
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What is the value of resistor R ? [Follow 1](https://www.wyzant.com/resources/answers/895150/toggle-follow) [Add comment](https://www.wyzant.com/resources/answers/895150/value-of-resistor#new-comment) More [Report](https://www.wyzant.com/resources/answers/895150/report-reason) ## 2 Answers By Expert Tutors By: ![]() Sadia S. answered 05/09/22 Tutor 4 (29) PHD Maths and Physics Tutor, Teacher, and Lecturer\! [See tutors like this](https://www.wyzant.com/match) [See tutors like this](https://www.wyzant.com/match) Given Data: Total resistance= (R+8)Ω voltage = 60V Current = 2.5 A We know that V=IR Put the data in above relation 60=2.5×(R+8) 60/2.5=R+8 24 = R+8 R=24-8 R= 16Ω Hence, the value of resistor R is 16Ω. If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics. [Upvote 1](https://www.wyzant.com/resources/answers/895150/answers/640534/upvote) [Downvote](https://www.wyzant.com/resources/answers/895150/answers/640534/downvote) [Add comment](https://www.wyzant.com/resources/answers/895150/value-of-resistor#new-comment) More [Report](https://www.wyzant.com/resources/answers/895150/answers/640534/report-reason) [![]()](https://www.wyzant.com/Tutors/CA/Sacramento/9843762/) [David C.](https://www.wyzant.com/Tutors/CA/Sacramento/9843762/) answered 05/09/22 Tutor 4\.4 (47) [Low Cost Math and Science Tutor](https://www.wyzant.com/Tutors/CA/Sacramento/9843762/) [About this tutor ›](https://www.wyzant.com/Tutors/CA/Sacramento/9843762/) [About this tutor ›](https://www.wyzant.com/Tutors/CA/Sacramento/9843762/) Total resistance = (8 + R) ohms = 60 V / 2.5 A = 24 ohms, so 8 + R = 24 ohms, so R = 16 ohms. [Upvote 1](https://www.wyzant.com/resources/answers/895150/answers/640532/upvote) [Downvote](https://www.wyzant.com/resources/answers/895150/answers/640532/downvote) [Comment 1](https://www.wyzant.com/resources/answers/895150/value-of-resistor#edit-comment) More [Report](https://www.wyzant.com/resources/answers/895150/answers/640532/report-reason) Lorde L. Thank you so much for your time, Sir\! [Report](https://www.wyzant.com/resources/comments/180789/report-reason) 05/09/22 ## Still looking for help? Get the right answer, fast. [Ask a question for free](https://www.wyzant.com/resources/answers/ask) Get a free answer to a quick problem. Most questions answered within 4 hours. #### OR [Find an Online Tutor Now](https://www.wyzant.com/match) Choose an expert and meet online. 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Readable Markdown	Given Data: Total resistance= (R+8)Ω voltage = 60V Current = 2.5 A We know that V=IR Put the data in above relation 60=2.5×(R+8) 60/2.5=R+8 24 = R+8 R=24-8 R= 16Ω Hence, the value of resistor R is 16Ω. If you like the way I have answered this question, then please leave a comment and send me a message letting me know you liked it ! You can take a look at over other problems I have solved here on Wyzant Ask an Expert using the link on my tutor page. Please contact me about setting up an online session to help you achieve your best potential test scores and grades in Mathematics, Statistics, and Physics.
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