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URLhttps://www.kristakingmath.com/blog/second-order-partial-derivatives
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Meta TitleHow to find all four second-order partial derivatives — Krista King Math | Online math help
Meta DescriptionWe already learned in single-variable calculus how to find second derivatives; we just took the derivative of the derivative. Remember how we even used the second derivative to help us with inflection points and concavity when we were learning optimization and sketching graphs?
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Here’s an example from single variable calculus of what a second derivative looks like: ???f(x)=2x^3??? ???f'(x)=6x^2??? ???f''(x)=12x??? Well, we can find the second derivative of a multivariable function in the same way. Except, instead of just one function that defines the second derivative (like ???f''(x)=12x??? above), we’ll need four functions that define the second derivative! Our second-order partial derivatives will be: ???f_{xx}=\frac{\partial}{\partial x}\left(\frac{\partial f}{\partial x}\right)=\frac{\partial^2f}{\partial x^2}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???x??? ???f_{yy}=\frac{\partial}{\partial y}\left(\frac{\partial f}{\partial y}\right)=\frac{\partial^2f}{\partial y^2}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???y??? ???f_{xy}=\frac{\partial}{\partial y}\left(\frac{\partial f}{\partial x}\right)=\frac{\partial^2f}{\partial y\partial x}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???x??? ???f_{yx}=\frac{\partial}{\partial x}\left(\frac{\partial f}{\partial y}\right)=\frac{\partial^2f}{\partial x\partial y}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???y??? That wording is a little bit complicated. We can think about like the illustration below, where we start with the original function in the first row, take first derivatives in the second row, and then second derivatives in the third row.
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[![Krista King Math \| Online math help](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1537392072530-1REILIR8TYPC00IS2EAU/KKM_primary-white.png)](https://www.kristakingmath.com/) [About](https://www.kristakingmath.com/about-krista) [Pricing](https://www.kristakingmath.com/pricing) [Login](https://courses.kristakingmath.com/auth/sign-in/) [Subscribe Risk Free](https://courses.kristakingmath.com/subscribe/) [About](https://www.kristakingmath.com/about-krista)[Pricing](https://www.kristakingmath.com/pricing)[Login](https://courses.kristakingmath.com/auth/sign-in/) [![Krista King Math \| Online math help](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1537392072530-1REILIR8TYPC00IS2EAU/KKM_primary-white.png)](https://www.kristakingmath.com/) Step-by-step math courses covering Pre-Algebra through Calculus 3. [Subscribe Risk Free](https://courses.kristakingmath.com/subscribe/) # How to find all four second-order partial derivatives ![Higher order partial derivatives blog post.jpeg](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1554845457050-6K515OK9GWUH4SC1ZYFM/Higher+order+partial+derivatives+blog+post.jpeg) ## There are four second-order partial derivatives for every multivariable function We already learned in single-variable calculus how to find second derivatives; we just took the derivative of the derivative. Remember how we even used the second derivative to help us with inflection points and concavity when we were learning optimization and sketching graphs? ![Krista King Math.jpg](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1531240577906-UIAUA4KAUI0TW2GDQK0M/Krista+King+Math.jpg) Hi! I'm krista. I create online courses to help you rock your math class. [Read more.](http://kristakingmath.com/) Here’s an example from single variable calculus of what a second derivative looks like: ???f(x)=2x^3??? ???f'(x)=6x^2??? ???f''(x)=12x??? Well, we can find the second derivative of a multivariable function in the same way. Except, instead of just one function that defines the second derivative (like ???f''(x)=12x??? above), we’ll need four functions that define the second derivative! Our second-order partial derivatives will be: ???f\_{xx}=\\frac{\\partial}{\\partial x}\\left(\\frac{\\partial f}{\\partial x}\\right)=\\frac{\\partial^2f}{\\partial x^2}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???x??? ???f\_{yy}=\\frac{\\partial}{\\partial y}\\left(\\frac{\\partial f}{\\partial y}\\right)=\\frac{\\partial^2f}{\\partial y^2}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???y??? ???f\_{xy}=\\frac{\\partial}{\\partial y}\\left(\\frac{\\partial f}{\\partial x}\\right)=\\frac{\\partial^2f}{\\partial y\\partial x}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???x??? ???f\_{yx}=\\frac{\\partial}{\\partial x}\\left(\\frac{\\partial f}{\\partial y}\\right)=\\frac{\\partial^2f}{\\partial x\\partial y}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???y??? That wording is a little bit complicated. We can think about like the illustration below, where we start with the original function in the first row, take first derivatives in the second row, and then second derivatives in the third row. ![tree diagram of higher-order derivatives](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1599226603070-95TPJKETXBL0ISF08YIR/tree+diagram+of+higher-order+derivatives) The good news is that, even though this looks like four second-order partial derivatives, it’s actually only three. That’s because the two second-order partial derivatives in the middle of the third row will always come out to be the same. Whether you start with the first-order partial derivative with respect to ???x???, and then take the partial derivative of that with respect to ???y???; or if you start with the first-order partial derivative with respect to ???y???, and then take the partial derivative of that with respect to ???x???; you’ll get the same answer in both cases. Which means our tree actually looks like this: ![the mixed second-order derivatives are equivalent](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1599226703723-MGI13VHY14S2MMPOMP27/the+mixed+second-order+derivatives+are+equivalent) ## How to calculate all four second-order partial derivatives for a multivariable function *** ![Krista King Math Signup.png](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1603386579776-6OCOSA9YN7OYTR6VTSWF/Krista+King+Math+Signup.png) ![Calculus 3 course.png](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1550464236135-7577EF59FCX7CR1G5UA2/Calculus+3+course.png) ## Take the course ### Want to learn more about Calculus 3? I have a step-by-step course for that. :) [Learn More](https://www.calculusexpert.com/library/by/category/calculus-iii/) *** ## Finding second-order partial derivatives **Example** Find the second-order partial derivatives of the multivariable function. ???f(x,y)=2x^2y??? We found the first-order partial derivatives of this function in a previous section, and they were ???f\_x(x,y)=4xy??? ???f\_y(x,y)=2x^2??? ![Higher order partial derivatives for Calculus 3.jpg](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1554845648933-52BD066QOWFVWOZLOYH4/Higher+order+partial+derivatives+for+Calculus+3.jpg) Excerpt The four second order partial derivatives are: ???f\_{xx}=\\frac{\\partial}{\\partial x}(4xy)=4y??? ???f\_{xy}=\\frac{\\partial}{\\partial x}\\left(2x^2\\right)=4x??? ???f\_{yx}=\\frac{\\partial}{\\partial y}(4xy)=4x??? ???f\_{yy}=\\frac{\\partial}{\\partial y}\\left(2x^2\\right)=0??? Notice that the mixed second-order partial derivative is the same, regardless of whether you take the partial derivative first with respect to ???x??? and then ???y???, or vice versa. ![Krista King.png](https://images.squarespace-cdn.com/content/v1/533db07de4b0d9f7ba7f1e77/1531243413505-L2JSZEAV47A16TR6BS72/Krista+King.png) *** ### Get access to the complete Calculus 3 course [Get started](https://www.calculusexpert.com/library/by/category/calculus-iii/) *** [Learn math](https://www.kristakingmath.com/blog/category/Learn+math)[Krista King](https://www.kristakingmath.com/blog?author=533db07be4b0f0bdc6e145a3) September 4, 2020 [math](https://www.kristakingmath.com/blog/tag/math), [learn online](https://www.kristakingmath.com/blog/tag/learn+online), [online course](https://www.kristakingmath.com/blog/tag/online+course), [online math](https://www.kristakingmath.com/blog/tag/online+math), [calculus 3](https://www.kristakingmath.com/blog/tag/calculus+3), [calculus iii](https://www.kristakingmath.com/blog/tag/calculus+iii), [calc 3](https://www.kristakingmath.com/blog/tag/calc+3), [calc iii](https://www.kristakingmath.com/blog/tag/calc+iii), [partial derivatives](https://www.kristakingmath.com/blog/tag/partial+derivatives), [partial differentiation](https://www.kristakingmath.com/blog/tag/partial+differentiation), [second-order partial derivatives](https://www.kristakingmath.com/blog/tag/second-order+partial+derivatives), [higher-order partial derivatives](https://www.kristakingmath.com/blog/tag/higher-order+partial+derivatives), [mixed partial derivatives](https://www.kristakingmath.com/blog/tag/mixed+partial+derivatives), [second-order partial derivative for x](https://www.kristakingmath.com/blog/tag/second-order+partial+derivative+for+x), [second-order partial derivative for y](https://www.kristakingmath.com/blog/tag/second-order+partial+derivative+for+y) [Facebook0](https://www.facebook.com/sharer/sharer.php?u=https%3A%2F%2Fwww.kristakingmath.com%2Fblog%2Fsecond-order-partial-derivatives) [Twitter](https://twitter.com/intent/tweet?url=https%3A%2F%2Fwww.kristakingmath.com%2Fblog%2Fsecond-order-partial-derivatives&text=We+already+learned+in+single-variable+calculus+how+to+find+second+derivatives%3B+we+just+took+the+...) 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Here’s an example from single variable calculus of what a second derivative looks like: ???f(x)=2x^3??? ???f'(x)=6x^2??? ???f''(x)=12x??? Well, we can find the second derivative of a multivariable function in the same way. Except, instead of just one function that defines the second derivative (like ???f''(x)=12x??? above), we’ll need four functions that define the second derivative! Our second-order partial derivatives will be: ???f\_{xx}=\\frac{\\partial}{\\partial x}\\left(\\frac{\\partial f}{\\partial x}\\right)=\\frac{\\partial^2f}{\\partial x^2}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???x??? ???f\_{yy}=\\frac{\\partial}{\\partial y}\\left(\\frac{\\partial f}{\\partial y}\\right)=\\frac{\\partial^2f}{\\partial y^2}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???y??? ???f\_{xy}=\\frac{\\partial}{\\partial y}\\left(\\frac{\\partial f}{\\partial x}\\right)=\\frac{\\partial^2f}{\\partial y\\partial x}??? The derivative with respect to ???y???, of the first-order partial derivative with respect to ???x??? ???f\_{yx}=\\frac{\\partial}{\\partial x}\\left(\\frac{\\partial f}{\\partial y}\\right)=\\frac{\\partial^2f}{\\partial x\\partial y}??? The derivative with respect to ???x???, of the first-order partial derivative with respect to ???y??? That wording is a little bit complicated. We can think about like the illustration below, where we start with the original function in the first row, take first derivatives in the second row, and then second derivatives in the third row.
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