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URLhttps://www.emathhelp.net/calculators/linear-algebra/eigenvalue-and-eigenvector-calculator/
Last Crawled2026-04-06 10:05:14 (9 hours ago)
First Indexed2017-02-22 11:52:39 (9 years ago)
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Meta TitleEigenvalues and Eigenvectors Calculator - eMathHelp
Meta DescriptionThe calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown.
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The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown. Related calculator: Characteristic Polynomial Calculator Your Input Find the eigenvalues and eigenvectors of $$$ \left[\begin{array}{cc}1 & 2\\0 & 3\end{array}\right] $$$ . Solution Start from forming a new matrix by subtracting $$$ \lambda $$$ from the diagonal entries of the given matrix: $$$ \left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right] $$$ . The determinant of the obtained matrix is $$$ \left(\lambda - 3\right) \left(\lambda - 1\right) $$$ (for steps, see determinant calculator ). Solve the equation $$$ \left(\lambda - 3\right) \left(\lambda - 1\right) = 0 $$$ . The roots are $$$ \lambda_{1} = 3 $$$ , $$$ \lambda_{2} = 1 $$$ (for steps, see equation solver ). These are the eigenvalues. Next, find the eigenvectors. $$$ \lambda = 3 $$$ $$$ \left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right] = \left[\begin{array}{cc}-2 & 2\\0 & 0\end{array}\right] $$$ The null space of this matrix is $$$ \left\{\left[\begin{array}{c}1\\1\end{array}\right]\right\} $$$ (for steps, see null space calculator ). This is the eigenvector. $$$ \lambda = 1 $$$ $$$ \left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right] = \left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right] $$$ The null space of this matrix is $$$ \left\{\left[\begin{array}{c}1\\0\end{array}\right]\right\} $$$ (for steps, see null space calculator ). This is the eigenvector. Answer Eigenvalue: $$$ 3 $$$ A , multiplicity: $$$ 1 $$$ A , eigenvector: $$$ \left[\begin{array}{c}1\\1\end{array}\right] $$$ A . Eigenvalue: $$$ 1 $$$ A , multiplicity: $$$ 1 $$$ A , eigenvector: $$$ \left[\begin{array}{c}1\\0\end{array}\right] $$$ A .
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Readable Markdown
The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown. Related calculator: [Characteristic Polynomial Calculator](https://www.emathhelp.net/calculators/linear-algebra/characteristic-polynomial-calculator/) Your Input **Find the eigenvalues and eigenvectors of \$\$\$\\left\[\\begin{array}{cc}1 & 2\\\\0 & 3\\end{array}\\right\]\$\$\$.** Solution Start from forming a new matrix by subtracting \$\$\$\\lambda\$\$\$ from the diagonal entries of the given matrix: \$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\]\$\$\$. The determinant of the obtained matrix is \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right)\$\$\$ (for steps, see [determinant calculator](https://www.emathhelp.net/calculators/linear-algebra/matrix-determinant-calculator/?i=%5B%5B1+-+lambda%2C2%5D%2C%5B0%2C3+-+lambda%5D%5D "determinant calculator")). Solve the equation \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right) = 0\$\$\$. The roots are \$\$\$\\lambda\_{1} = 3\$\$\$, \$\$\$\\lambda\_{2} = 1\$\$\$ (for steps, see [equation solver](https://www.emathhelp.net/calculators/algebra-2/equation-solver-calculator/?f=%28lambda+-+3%29%2A%28lambda+-+1%29&var=lambda "equation solver")). These are the eigenvalues. Next, find the eigenvectors. - \$\$\$\\lambda = 3\$\$\$ \$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}-2 & 2\\\\0 & 0\\end{array}\\right\]\$\$\$ The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B-2%2C2%5D%2C%5B0%2C0%5D%5D "null space calculator")). This is the eigenvector. - \$\$\$\\lambda = 1\$\$\$ \$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}0 & 2\\\\0 & 2\\end{array}\\right\]\$\$\$ The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B0%2C2%5D%2C%5B0%2C2%5D%5D "null space calculator")). This is the eigenvector. Answer **Eigenvalue: \$\$\$3\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\$\$\$A.** **Eigenvalue: \$\$\$1\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\$\$\$A.**
Shard63 (laksa)
Root Hash16951690241190635063
Unparsed URLnet,emathhelp!www,/calculators/linear-algebra/eigenvalue-and-eigenvector-calculator/ s443