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| Meta Title | Eigenvalues and Eigenvectors Calculator - eMathHelp |
| Meta Description | The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown. |
| Meta Canonical | null |
| Boilerpipe Text | The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown.
Related calculator:
Characteristic Polynomial Calculator
Your Input
Find the eigenvalues and eigenvectors of
$$$
\left[\begin{array}{cc}1 & 2\\0 & 3\end{array}\right]
$$$
.
Solution
Start from forming a new matrix by subtracting
$$$
\lambda
$$$
from the diagonal entries of the given matrix:
$$$
\left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right]
$$$
.
The determinant of the obtained matrix is
$$$
\left(\lambda - 3\right) \left(\lambda - 1\right)
$$$
(for steps, see
determinant calculator
).
Solve the equation
$$$
\left(\lambda - 3\right) \left(\lambda - 1\right) = 0
$$$
.
The roots are
$$$
\lambda_{1} = 3
$$$
,
$$$
\lambda_{2} = 1
$$$
(for steps, see
equation solver
).
These are the eigenvalues.
Next, find the eigenvectors.
$$$
\lambda = 3
$$$
$$$
\left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right] = \left[\begin{array}{cc}-2 & 2\\0 & 0\end{array}\right]
$$$
The null space of this matrix is
$$$
\left\{\left[\begin{array}{c}1\\1\end{array}\right]\right\}
$$$
(for steps, see
null space calculator
).
This is the eigenvector.
$$$
\lambda = 1
$$$
$$$
\left[\begin{array}{cc}1 - \lambda & 2\\0 & 3 - \lambda\end{array}\right] = \left[\begin{array}{cc}0 & 2\\0 & 2\end{array}\right]
$$$
The null space of this matrix is
$$$
\left\{\left[\begin{array}{c}1\\0\end{array}\right]\right\}
$$$
(for steps, see
null space calculator
).
This is the eigenvector.
Answer
Eigenvalue:
$$$
3
$$$
A
, multiplicity:
$$$
1
$$$
A
, eigenvector:
$$$
\left[\begin{array}{c}1\\1\end{array}\right]
$$$
A
.
Eigenvalue:
$$$
1
$$$
A
, multiplicity:
$$$
1
$$$
A
, eigenvector:
$$$
\left[\begin{array}{c}1\\0\end{array}\right]
$$$
A
. |
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# Eigenvalues and Eigenvectors Calculator
## Calculate eigenvalues and eigenvectors step by step
The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown.
Related calculator: [Characteristic Polynomial Calculator](https://www.emathhelp.net/calculators/linear-algebra/characteristic-polynomial-calculator/)
### Your Input
**Find the eigenvalues and eigenvectors of \$\$\$\\left\[\\begin{array}{cc}1 & 2\\\\0 & 3\\end{array}\\right\]\$\$\$.**
### Solution
Start from forming a new matrix by subtracting \$\$\$\\lambda\$\$\$ from the diagonal entries of the given matrix: \$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\]\$\$\$.
The determinant of the obtained matrix is \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right)\$\$\$ (for steps, see [determinant calculator](https://www.emathhelp.net/calculators/linear-algebra/matrix-determinant-calculator/?i=%5B%5B1+-+lambda%2C2%5D%2C%5B0%2C3+-+lambda%5D%5D "determinant calculator")).
Solve the equation \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right) = 0\$\$\$.
The roots are \$\$\$\\lambda\_{1} = 3\$\$\$, \$\$\$\\lambda\_{2} = 1\$\$\$ (for steps, see [equation solver](https://www.emathhelp.net/calculators/algebra-2/equation-solver-calculator/?f=%28lambda+-+3%29%2A%28lambda+-+1%29&var=lambda "equation solver")).
These are the eigenvalues.
Next, find the eigenvectors.
- \$\$\$\\lambda = 3\$\$\$
\$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}-2 & 2\\\\0 & 0\\end{array}\\right\]\$\$\$
The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B-2%2C2%5D%2C%5B0%2C0%5D%5D "null space calculator")).
This is the eigenvector.
- \$\$\$\\lambda = 1\$\$\$
\$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}0 & 2\\\\0 & 2\\end{array}\\right\]\$\$\$
The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B0%2C2%5D%2C%5B0%2C2%5D%5D "null space calculator")).
This is the eigenvector.
### Answer
**Eigenvalue: \$\$\$3\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\$\$\$A.**
**Eigenvalue: \$\$\$1\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\$\$\$A.**
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| Readable Markdown | The calculator will find the eigenvalues and eigenvectors (eigenspace) of the given square matrix, with steps shown.
Related calculator: [Characteristic Polynomial Calculator](https://www.emathhelp.net/calculators/linear-algebra/characteristic-polynomial-calculator/)
Your Input
**Find the eigenvalues and eigenvectors of \$\$\$\\left\[\\begin{array}{cc}1 & 2\\\\0 & 3\\end{array}\\right\]\$\$\$.**
Solution
Start from forming a new matrix by subtracting \$\$\$\\lambda\$\$\$ from the diagonal entries of the given matrix: \$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\]\$\$\$.
The determinant of the obtained matrix is \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right)\$\$\$ (for steps, see [determinant calculator](https://www.emathhelp.net/calculators/linear-algebra/matrix-determinant-calculator/?i=%5B%5B1+-+lambda%2C2%5D%2C%5B0%2C3+-+lambda%5D%5D "determinant calculator")).
Solve the equation \$\$\$\\left(\\lambda - 3\\right) \\left(\\lambda - 1\\right) = 0\$\$\$.
The roots are \$\$\$\\lambda\_{1} = 3\$\$\$, \$\$\$\\lambda\_{2} = 1\$\$\$ (for steps, see [equation solver](https://www.emathhelp.net/calculators/algebra-2/equation-solver-calculator/?f=%28lambda+-+3%29%2A%28lambda+-+1%29&var=lambda "equation solver")).
These are the eigenvalues.
Next, find the eigenvectors.
- \$\$\$\\lambda = 3\$\$\$
\$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}-2 & 2\\\\0 & 0\\end{array}\\right\]\$\$\$
The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B-2%2C2%5D%2C%5B0%2C0%5D%5D "null space calculator")).
This is the eigenvector.
- \$\$\$\\lambda = 1\$\$\$
\$\$\$\\left\[\\begin{array}{cc}1 - \\lambda & 2\\\\0 & 3 - \\lambda\\end{array}\\right\] = \\left\[\\begin{array}{cc}0 & 2\\\\0 & 2\\end{array}\\right\]\$\$\$
The null space of this matrix is \$\$\$\\left\\{\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\\right\\}\$\$\$ (for steps, see [null space calculator](https://www.emathhelp.net/calculators/linear-algebra/null-space-calculator/?i=%5B%5B0%2C2%5D%2C%5B0%2C2%5D%5D "null space calculator")).
This is the eigenvector.
Answer
**Eigenvalue: \$\$\$3\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\1\\end{array}\\right\]\$\$\$A.**
**Eigenvalue: \$\$\$1\$\$\$A, multiplicity: \$\$\$1\$\$\$A, eigenvector: \$\$\$\\left\[\\begin{array}{c}1\\\\0\\end{array}\\right\]\$\$\$A.** |
| Shard | 63 (laksa) |
| Root Hash | 16951690241190635063 |
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