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URLhttps://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/10
Last Crawled2025-10-17 00:37:00 (5 months ago)
First Indexednot set
HTTP Status Code200
Meta TitleCalculating the value of the series resistor - Practical electrical and electronic circuits - National 5 Physics Revision - BBC Bitesize
Meta DescriptionIn National 5 Physics examine the current and voltage in series and parallel circuits to formulate rules and determine unknown values.
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To use one of these LEDs in a circuit powered by a \(6V\) battery close battery A chemical supply of electrical energy. For example, common battery voltages include 1.5 V and 9 V. , we would calculate the required series resistance as follows.
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[National 5](https://www.bbc.co.uk/bitesize/levels/z6gw2hv) # Practical electrical and electronic circuitsCalculating the value of the series resistor Measurement and analysis of current and voltage in simple circuits allows us to formulate rules and predict unknown values. Part of [Physics](https://www.bbc.co.uk/bitesize/subjects/z6fsgk7)[Electricity](https://www.bbc.co.uk/bitesize/topics/zs2m97h) Save to My Bitesize Save to My Bitesize Saving Saved Removing Remove from My Bitesize close panel ## In this guide 1. [Revise](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/1) 2. [Video](https://www.bbc.co.uk/bitesize/guides/zk37hyc/video) 3. [Test](https://www.bbc.co.uk/bitesize/guides/zk37hyc/test) ## Pages 1. [Practical electrical and electronic circuits](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/1) 2. [Voltage across components in a series circuit](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/2) 3. [Parallel circuits](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/3) 4. [Voltage across components in a parallel circuit](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/4) 5. [Measuring resistance](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/5) 6. [Electrical and electronic components](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/6) 7. [Input devices](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/7) 8. [Voltage dividers](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/8) 9. [Output devices](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/9) 10. [Calculating the value of the series resistor](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/10) 11. [Process devices](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/11) ## Calculating the value of the series resistor To calculate the resistance of the series resistor required, we need to look at the current and voltage values recommended by the LED manufacturer. Suppose a manufacturer recommends a maximum voltage of \\(2V\\) across their LEDs and maximum current of \\(10mA\\). To use one of these LEDs in a circuit powered by a \\(6V\\) battery close batteryA chemical supply of electrical energy. For example, common battery voltages include 1.5 V and 9 V., we would calculate the required series resistance as follows. ![Circuit with a 6 V battery, resistor R and an LED connected in series.](https://bam.files.bbci.co.uk/bam/live/content/z99r87h/small) Using properties of a series circuit, the sum of the voltages across the LED and resistor R must equal the supply voltage. \\({V\_s} = {V\_{LED}} + {V\_R}\\) Now substitute the supply voltage (\\(6V\\))and the maximum LED voltage (\\(2V\\)). \\(6 = 2 + {V\_R}\\) \\({V\_R} = 4V\\) So the voltage across the series resistor will be \\(4V\\). In a series circuit, the current is the same at all points. So if the current in the LED is \\(10 mA\\), the current in resistor \\(R\\) is also \\(10 mA\\). Using Ohm close OhmsThe unit of electrical resistance, whose symbol is Ω.'s Law, calculate the value of resistor required. \\(V = IR\\) Remember: \\(I\\)must be changed from \\(mA\\) to \\(A\\)(\\(10 mA = 0.01 A\\)) \\(4 = 0.01 \\times R\\) \\(R = \\frac{4}{{0.01}}\\) \\(R = 400\\Omega\\) A \\(400 Ω\\) resistor is required. ## Question A LED takes a current of \\(12.5 mA\\) when the voltage across it is 2 V. Draw a suitable circuit and calculate the value of the series resistor needed to operate the LED from a \\(9 V\\) battery. ### Show answerHide answer The circuit needed is: ![Circuit with a 9 V battery, resistor R and an LED connected in series. The LED is labelled 2 V.](https://bam.files.bbci.co.uk/bam/live/content/zkkcd2p/small) Check that your LED symbol points towards the negative terminal (the shorter line) of the battery symbol. To calculate the value of the series resistor, use the following steps: The voltage of the supply splits up across components in series, so the voltage across the resistor is \\((9 - 2) = 7 V\\) The current is the same through components in series, so the current in the resistor is 12.5 \\(mA (0.0125 A)\\). Using the relationship between voltage, current and resistance gives: \\(R = \\frac{V}{I}\\) \\(= \\frac{7}{{0.0125}}\\) \\(= 560\\Omega\\) A \\(560 Ω\\) resistor is required. [Next pageProcess devices](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/11) [Previous pageOutput devices](https://www.bbc.co.uk/bitesize/guides/zk37hyc/revision/9) ## More guides on this topic - [Electrical charge carriers](https://www.bbc.co.uk/bitesize/guides/ztf74qt/revision/1) - [Potential differences (voltage)](https://www.bbc.co.uk/bitesize/guides/zsrpfg8/revision/1) - [Ohm's Law](https://www.bbc.co.uk/bitesize/guides/z8b2pv4/revision/1) - [Electrical power](https://www.bbc.co.uk/bitesize/guides/zsgtw6f/revision/1) - [Conductors and insulators](https://www.bbc.co.uk/bitesize/topics/zs2m97h/watch/z3gg9j6) ## Related links - [BBC Science](http://www.bbc.co.uk/science/0/) - [BBC News: Science](http://www.bbc.co.uk/news/science_and_environment/) - [BBC Lab UK](http://www.bbc.co.uk/labuk/) - [SQA National 5 Physics](http://www.sqa.org.uk/sqa/45731.html) - [Physics.org](http://www.physics.org/) - [The Physics Classroom](http://www.physicsclassroom.com/) - [Physics Central](http://www.physicscentral.com/) Language: - [Home](https://www.bbc.com/) - [News](https://www.bbc.com/news) - [Sport](https://www.bbc.com/sport) - [Earth](https://www.bbc.com/future/earth) - [Reel](https://www.bbc.com/reel) - [Worklife](https://www.bbc.com/worklife) - [Travel](https://www.bbc.com/travel) - [Culture](https://www.bbc.com/culture) - [Future](https://www.bbc.com/future) - [Music](https://www.bbc.com/culture/music) - [TV](https://www.bbc.co.uk/schedules/p00fzl9m) - [Weather](https://www.bbc.com/weather) - [Sounds](https://www.bbc.co.uk/sounds) - [Terms of Use](https://www.bbc.co.uk/usingthebbc/terms) - [About the BBC](https://www.bbc.co.uk/aboutthebbc) - [Privacy Policy](https://www.bbc.com/usingthebbc/privacy) - [Cookies](https://www.bbc.com/usingthebbc/cookies) - [Accessibility Help](https://www.bbc.co.uk/accessibility) - [Parental Guidance](https://www.bbc.co.uk/iplayer/guidance) - [Contact the BBC](https://www.bbc.co.uk/contact) - [BBC emails for you](https://www.bbc.co.uk/bbcnewsletter) - [Advertise with us](https://www.bbc.com/advertisingcontact/) Copyright © 2025 BBC. 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