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Chicken and Rabbit problem - [Tap to switch levels]() - [Numbers]() - [Measurement]() - [Data Analysis]() - [Geometry]() - [Speed]() - [Others]() - [P5 Maths]() - [P4 Maths]() #### [Tap to switch levels](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_all) #### [Numbers](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_111) [What does the number stand for?](https://psle-math.com/student/test/what-does-the-number-stand-for) [Nearest number](https://psle-math.com/student/test/nearest-number) [Which digit is in the place?](https://psle-math.com/student/test/which-digit-is-in-the-place) [Round off to the nearest number](https://psle-math.com/student/test/round-off-to-the-nearest-number) [Number divide](https://psle-math.com/student/test/number-divide) [Find the fraction nearest to 1](https://psle-math.com/student/test/find-the-fraction-nearest-to-1) [Sort fraction numbers](https://psle-math.com/student/test/sort-fraction-numbers) [Find the largest or smallest fraction](https://psle-math.com/student/test/find-the-largest-or-smallest-fraction) [Fraction to decimal](https://psle-math.com/student/test/fraction-to-decimal) [Convert decimal to a mixed fraction.](https://psle-math.com/student/test/convert-decimal-to-a-mixed-fraction) [Fraction - 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Given that the total number of legs on the farm is 108, find the number of Chickens **A** 48 **B** 53 **C** 49 **D** 44 Submit Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 51\\times2=102 \\end{array} legs. However, there are actually 108 legs. Therefore, there are \\begin{array}{rcl} 108-102=6 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Chickens is \\begin{array}{rcl} 51-3=48. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 51\\times4=204 \\end{array} legs. However, there are actually only 108 legs. Therefore, there are a shortage of \\begin{array}{rcl} 204-108=96 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 96\\div2=48. \\end{array} The number of Cows is \\begin{array}{rcl} 51-48=3. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_0) 48 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 51\\times2=102 \\end{array} legs. However, there are actually 108 legs. Therefore, there are \\begin{array}{rcl} 108-102=6 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Chickens is \\begin{array}{rcl} 51-3=48. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 51\\times4=204 \\end{array} legs. However, there are actually only 108 legs. Therefore, there are a shortage of \\begin{array}{rcl} 204-108=96 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 96\\div2=48. \\end{array} The number of Cows is \\begin{array}{rcl} 51-48=3. \\end{array} There are a total of 23 Chickens and Horses on a farm. Given that the total number of legs on the farm is 72, find the number of Chickens **A** 18 **B** 11 **C** 10 **D** 12 Prev Submit Prev Next Sorry. Please check the correct answer below. #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_1) 10 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 23\\times2=46 \\end{array} legs. However, there are actually 72 legs. Therefore, there are \\begin{array}{rcl} 72-46=26 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 26\\div2=13. \\end{array} The number of Chickens is \\begin{array}{rcl} 23-13=10. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 23\\times4=92 \\end{array} legs. However, there are actually only 72 legs. Therefore, there are a shortage of \\begin{array}{rcl} 92-72=20 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 20\\div2=10. \\end{array} The number of Horses is \\begin{array}{rcl} 23-10=13. \\end{array} There are a total of 79 Gooses and Dogs on a farm. Given that the total number of legs on the farm is 228, find the number of Dogs **A** 34 **B** 35 **C** 39 **D** 36 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 79\\times2=158 \\end{array} legs. However, there are actually 228 legs. Therefore, there are \\begin{array}{rcl} 228-158=70 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 70\\div2=35. \\end{array} The number of Gooses is \\begin{array}{rcl} 79-35=44. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 79\\times4=316 \\end{array} legs. However, there are actually only 228 legs. Therefore, there are a shortage of \\begin{array}{rcl} 316-228=88 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Dogs is \\begin{array}{rcl} 79-44=35. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_2) 35 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 79\\times2=158 \\end{array} legs. However, there are actually 228 legs. Therefore, there are \\begin{array}{rcl} 228-158=70 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 70\\div2=35. \\end{array} The number of Gooses is \\begin{array}{rcl} 79-35=44. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 79\\times4=316 \\end{array} legs. However, there are actually only 228 legs. Therefore, there are a shortage of \\begin{array}{rcl} 316-228=88 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Dogs is \\begin{array}{rcl} 79-44=35. \\end{array} There are a total of 28 Ducks and Pigs on a farm. Given that the total number of legs on the farm is 88, find the number of Pigs **A** 16 **B** 21 **C** 20 **D** 13 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 28\\times2=56 \\end{array} legs. However, there are actually 88 legs. Therefore, there are \\begin{array}{rcl} 88-56=32 \\end{array} extra legs. If we replace one Duck by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Ducks is \\begin{array}{rcl} 28-16=12. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 28\\times4=112 \\end{array} legs. However, there are actually only 88 legs. Therefore, there are a shortage of \\begin{array}{rcl} 112-88=24 \\end{array} legs. If we replace one Pig by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Pigs is \\begin{array}{rcl} 28-12=16. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_3) 16 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 28\\times2=56 \\end{array} legs. However, there are actually 88 legs. Therefore, there are \\begin{array}{rcl} 88-56=32 \\end{array} extra legs. If we replace one Duck by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Ducks is \\begin{array}{rcl} 28-16=12. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 28\\times4=112 \\end{array} legs. However, there are actually only 88 legs. Therefore, there are a shortage of \\begin{array}{rcl} 112-88=24 \\end{array} legs. If we replace one Pig by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Pigs is \\begin{array}{rcl} 28-12=16. \\end{array} There are a total of 69 Ducks and Donkeys on a farm. Given that the total number of legs on the farm is 152, find the number of Ducks **A** 70 **B** 62 **C** 65 **D** 60 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 69\\times2=138 \\end{array} legs. However, there are actually 152 legs. Therefore, there are \\begin{array}{rcl} 152-138=14 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 14\\div2=7. \\end{array} The number of Ducks is \\begin{array}{rcl} 69-7=62. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 69\\times4=276 \\end{array} legs. However, there are actually only 152 legs. Therefore, there are a shortage of \\begin{array}{rcl} 276-152=124 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 124\\div2=62. \\end{array} The number of Donkeys is \\begin{array}{rcl} 69-62=7. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_4) 62 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 69\\times2=138 \\end{array} legs. However, there are actually 152 legs. Therefore, there are \\begin{array}{rcl} 152-138=14 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 14\\div2=7. \\end{array} The number of Ducks is \\begin{array}{rcl} 69-7=62. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 69\\times4=276 \\end{array} legs. However, there are actually only 152 legs. Therefore, there are a shortage of \\begin{array}{rcl} 276-152=124 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 124\\div2=62. \\end{array} The number of Donkeys is \\begin{array}{rcl} 69-62=7. \\end{array} There are a total of 119 Ducks and Donkeys on a farm. Given that the total number of legs on the farm is 272, find the number of Donkeys **A** 25 **B** 17 **C** 12 **D** 16 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 119\\times2=238 \\end{array} legs. However, there are actually 272 legs. Therefore, there are \\begin{array}{rcl} 272-238=34 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 34\\div2=17. \\end{array} The number of Ducks is \\begin{array}{rcl} 119-17=102. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 119\\times4=476 \\end{array} legs. However, there are actually only 272 legs. Therefore, there are a shortage of \\begin{array}{rcl} 476-272=204 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 204\\div2=102. \\end{array} The number of Donkeys is \\begin{array}{rcl} 119-102=17. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_5) 17 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 119\\times2=238 \\end{array} legs. However, there are actually 272 legs. Therefore, there are \\begin{array}{rcl} 272-238=34 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 34\\div2=17. \\end{array} The number of Ducks is \\begin{array}{rcl} 119-17=102. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 119\\times4=476 \\end{array} legs. However, there are actually only 272 legs. Therefore, there are a shortage of \\begin{array}{rcl} 476-272=204 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 204\\div2=102. \\end{array} The number of Donkeys is \\begin{array}{rcl} 119-102=17. \\end{array} There are a total of 72 Ducks and Rabbits on a farm. Given that the total number of legs on the farm is 176, find the number of Rabbits **A** 18 **B** 13 **C** 16 **D** 20 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 72\\times2=144 \\end{array} legs. However, there are actually 176 legs. Therefore, there are \\begin{array}{rcl} 176-144=32 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Ducks is \\begin{array}{rcl} 72-16=56. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 72\\times4=288 \\end{array} legs. However, there are actually only 176 legs. Therefore, there are a shortage of \\begin{array}{rcl} 288-176=112 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 112\\div2=56. \\end{array} The number of Rabbits is \\begin{array}{rcl} 72-56=16. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_6) 16 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 72\\times2=144 \\end{array} legs. However, there are actually 176 legs. Therefore, there are \\begin{array}{rcl} 176-144=32 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Ducks is \\begin{array}{rcl} 72-16=56. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 72\\times4=288 \\end{array} legs. However, there are actually only 176 legs. Therefore, there are a shortage of \\begin{array}{rcl} 288-176=112 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 112\\div2=56. \\end{array} The number of Rabbits is \\begin{array}{rcl} 72-56=16. \\end{array} There are a total of 65 Chickens and Cows on a farm. Given that the total number of legs on the farm is 252, find the number of Cows **A** 65 **B** 56 **C** 61 **D** 58 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 65\\times2=130 \\end{array} legs. However, there are actually 252 legs. Therefore, there are \\begin{array}{rcl} 252-130=122 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 122\\div2=61. \\end{array} The number of Chickens is \\begin{array}{rcl} 65-61=4. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 65\\times4=260 \\end{array} legs. However, there are actually only 252 legs. Therefore, there are a shortage of \\begin{array}{rcl} 260-252=8 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Cows is \\begin{array}{rcl} 65-4=61. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_7) 61 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 65\\times2=130 \\end{array} legs. However, there are actually 252 legs. Therefore, there are \\begin{array}{rcl} 252-130=122 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 122\\div2=61. \\end{array} The number of Chickens is \\begin{array}{rcl} 65-61=4. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 65\\times4=260 \\end{array} legs. However, there are actually only 252 legs. Therefore, there are a shortage of \\begin{array}{rcl} 260-252=8 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Cows is \\begin{array}{rcl} 65-4=61. \\end{array} There are a total of 64 Chickens and Goats on a farm. Given that the total number of legs on the farm is 140, find the number of Goats **A** 3 **B** 9 **C** 12 **D** 6 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 64\\times2=128 \\end{array} legs. However, there are actually 140 legs. Therefore, there are \\begin{array}{rcl} 140-128=12 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Chickens is \\begin{array}{rcl} 64-6=58. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 64\\times4=256 \\end{array} legs. However, there are actually only 140 legs. Therefore, there are a shortage of \\begin{array}{rcl} 256-140=116 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 116\\div2=58. \\end{array} The number of Goats is \\begin{array}{rcl} 64-58=6. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_8) 6 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 64\\times2=128 \\end{array} legs. However, there are actually 140 legs. Therefore, there are \\begin{array}{rcl} 140-128=12 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Chickens is \\begin{array}{rcl} 64-6=58. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 64\\times4=256 \\end{array} legs. However, there are actually only 140 legs. Therefore, there are a shortage of \\begin{array}{rcl} 256-140=116 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 116\\div2=58. \\end{array} The number of Goats is \\begin{array}{rcl} 64-58=6. \\end{array} There are a total of 20 Gooses and Goats on a farm. Given that the total number of legs on the farm is 64, find the number of Gooses **A** 8 **B** 7 **C** 5 **D** 10 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 20\\times2=40 \\end{array} legs. However, there are actually 64 legs. Therefore, there are \\begin{array}{rcl} 64-40=24 \\end{array} extra legs. If we replace one Goose by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Gooses is \\begin{array}{rcl} 20-12=8. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 20\\times4=80 \\end{array} legs. However, there are actually only 64 legs. Therefore, there are a shortage of \\begin{array}{rcl} 80-64=16 \\end{array} legs. If we replace one Goat by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Goats is \\begin{array}{rcl} 20-8=12. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_9) 8 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 20\\times2=40 \\end{array} legs. However, there are actually 64 legs. Therefore, there are \\begin{array}{rcl} 64-40=24 \\end{array} extra legs. If we replace one Goose by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Gooses is \\begin{array}{rcl} 20-12=8. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 20\\times4=80 \\end{array} legs. However, there are actually only 64 legs. Therefore, there are a shortage of \\begin{array}{rcl} 80-64=16 \\end{array} legs. If we replace one Goat by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Goats is \\begin{array}{rcl} 20-8=12. \\end{array} There are a total of 69 Gooses and Dogs on a farm. Given that the total number of legs on the farm is 144, find the number of Dogs **A** 5 **B** 7 **C** 3 **D** 9 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 69\\times2=138 \\end{array} legs. However, there are actually 144 legs. Therefore, there are \\begin{array}{rcl} 144-138=6 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Gooses is \\begin{array}{rcl} 69-3=66. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 69\\times4=276 \\end{array} legs. However, there are actually only 144 legs. Therefore, there are a shortage of \\begin{array}{rcl} 276-144=132 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 132\\div2=66. \\end{array} The number of Dogs is \\begin{array}{rcl} 69-66=3. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_10) 3 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 69\\times2=138 \\end{array} legs. However, there are actually 144 legs. Therefore, there are \\begin{array}{rcl} 144-138=6 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Gooses is \\begin{array}{rcl} 69-3=66. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 69\\times4=276 \\end{array} legs. However, there are actually only 144 legs. Therefore, there are a shortage of \\begin{array}{rcl} 276-144=132 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 132\\div2=66. \\end{array} The number of Dogs is \\begin{array}{rcl} 69-66=3. \\end{array} There are a total of 118 Chickens and Cows on a farm. Given that the total number of legs on the farm is 276, find the number of Cows **A** 24 **B** 26 **C** 20 **D** 15 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 118\\times2=236 \\end{array} legs. However, there are actually 276 legs. Therefore, there are \\begin{array}{rcl} 276-236=40 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Chickens is \\begin{array}{rcl} 118-20=98. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 118\\times4=472 \\end{array} legs. However, there are actually only 276 legs. Therefore, there are a shortage of \\begin{array}{rcl} 472-276=196 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 196\\div2=98. \\end{array} The number of Cows is \\begin{array}{rcl} 118-98=20. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_11) 20 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 118\\times2=236 \\end{array} legs. However, there are actually 276 legs. Therefore, there are \\begin{array}{rcl} 276-236=40 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Chickens is \\begin{array}{rcl} 118-20=98. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 118\\times4=472 \\end{array} legs. However, there are actually only 276 legs. Therefore, there are a shortage of \\begin{array}{rcl} 472-276=196 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 196\\div2=98. \\end{array} The number of Cows is \\begin{array}{rcl} 118-98=20. \\end{array} There are a total of 36 Gooses and Donkeys on a farm. Given that the total number of legs on the farm is 76, find the number of Gooses **A** 36 **B** 34 **C** 37 **D** 39 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 36\\times2=72 \\end{array} legs. However, there are actually 76 legs. Therefore, there are \\begin{array}{rcl} 76-72=4 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 4\\div2=2. \\end{array} The number of Gooses is \\begin{array}{rcl} 36-2=34. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 36\\times4=144 \\end{array} legs. However, there are actually only 76 legs. Therefore, there are a shortage of \\begin{array}{rcl} 144-76=68 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Donkeys is \\begin{array}{rcl} 36-34=2. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_12) 34 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 36\\times2=72 \\end{array} legs. However, there are actually 76 legs. Therefore, there are \\begin{array}{rcl} 76-72=4 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 4\\div2=2. \\end{array} The number of Gooses is \\begin{array}{rcl} 36-2=34. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 36\\times4=144 \\end{array} legs. However, there are actually only 76 legs. Therefore, there are a shortage of \\begin{array}{rcl} 144-76=68 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Donkeys is \\begin{array}{rcl} 36-34=2. \\end{array} There are a total of 33 Gooses and Rabbits on a farm. Given that the total number of legs on the farm is 100, find the number of Gooses **A** 24 **B** 16 **C** 19 **D** 14 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 33\\times2=66 \\end{array} legs. However, there are actually 100 legs. Therefore, there are \\begin{array}{rcl} 100-66=34 \\end{array} extra legs. If we replace one Goose by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 34\\div2=17. \\end{array} The number of Gooses is \\begin{array}{rcl} 33-17=16. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 33\\times4=132 \\end{array} legs. However, there are actually only 100 legs. Therefore, there are a shortage of \\begin{array}{rcl} 132-100=32 \\end{array} legs. If we replace one Rabbit by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Rabbits is \\begin{array}{rcl} 33-16=17. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_13) 16 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 33\\times2=66 \\end{array} legs. However, there are actually 100 legs. Therefore, there are \\begin{array}{rcl} 100-66=34 \\end{array} extra legs. If we replace one Goose by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 34\\div2=17. \\end{array} The number of Gooses is \\begin{array}{rcl} 33-17=16. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 33\\times4=132 \\end{array} legs. However, there are actually only 100 legs. Therefore, there are a shortage of \\begin{array}{rcl} 132-100=32 \\end{array} legs. If we replace one Rabbit by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Rabbits is \\begin{array}{rcl} 33-16=17. \\end{array} There are a total of 78 Chickens and Pigs on a farm. Given that the total number of legs on the farm is 248, find the number of Chickens **A** 30 **B** 31 **C** 32 **D** 40 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 78\\times2=156 \\end{array} legs. However, there are actually 248 legs. Therefore, there are \\begin{array}{rcl} 248-156=92 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 92\\div2=46. \\end{array} The number of Chickens is \\begin{array}{rcl} 78-46=32. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 78\\times4=312 \\end{array} legs. However, there are actually only 248 legs. Therefore, there are a shortage of \\begin{array}{rcl} 312-248=64 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Pigs is \\begin{array}{rcl} 78-32=46. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_14) 32 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 78\\times2=156 \\end{array} legs. However, there are actually 248 legs. Therefore, there are \\begin{array}{rcl} 248-156=92 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 92\\div2=46. \\end{array} The number of Chickens is \\begin{array}{rcl} 78-46=32. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 78\\times4=312 \\end{array} legs. However, there are actually only 248 legs. Therefore, there are a shortage of \\begin{array}{rcl} 312-248=64 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Pigs is \\begin{array}{rcl} 78-32=46. \\end{array} There are a total of 86 Gooses and Horses on a farm. Given that the total number of legs on the farm is 196, find the number of Horses **A** 13 **B** 7 **C** 12 **D** 16 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 86\\times2=172 \\end{array} legs. However, there are actually 196 legs. Therefore, there are \\begin{array}{rcl} 196-172=24 \\end{array} extra legs. If we replace one Goose by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Gooses is \\begin{array}{rcl} 86-12=74. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 86\\times4=344 \\end{array} legs. However, there are actually only 196 legs. Therefore, there are a shortage of \\begin{array}{rcl} 344-196=148 \\end{array} legs. If we replace one Horse by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 148\\div2=74. \\end{array} The number of Horses is \\begin{array}{rcl} 86-74=12. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_15) 12 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 86\\times2=172 \\end{array} legs. However, there are actually 196 legs. Therefore, there are \\begin{array}{rcl} 196-172=24 \\end{array} extra legs. If we replace one Goose by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Gooses is \\begin{array}{rcl} 86-12=74. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 86\\times4=344 \\end{array} legs. However, there are actually only 196 legs. Therefore, there are a shortage of \\begin{array}{rcl} 344-196=148 \\end{array} legs. If we replace one Horse by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 148\\div2=74. \\end{array} The number of Horses is \\begin{array}{rcl} 86-74=12. \\end{array} There are a total of 53 Ducks and Rabbits on a farm. Given that the total number of legs on the farm is 172, find the number of Rabbits **A** 33 **B** 29 **C** 38 **D** 31 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 53\\times2=106 \\end{array} legs. However, there are actually 172 legs. Therefore, there are \\begin{array}{rcl} 172-106=66 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 66\\div2=33. \\end{array} The number of Ducks is \\begin{array}{rcl} 53-33=20. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 53\\times4=212 \\end{array} legs. However, there are actually only 172 legs. Therefore, there are a shortage of \\begin{array}{rcl} 212-172=40 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Rabbits is \\begin{array}{rcl} 53-20=33. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_16) 33 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 53\\times2=106 \\end{array} legs. However, there are actually 172 legs. Therefore, there are \\begin{array}{rcl} 172-106=66 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 66\\div2=33. \\end{array} The number of Ducks is \\begin{array}{rcl} 53-33=20. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 53\\times4=212 \\end{array} legs. However, there are actually only 172 legs. Therefore, there are a shortage of \\begin{array}{rcl} 212-172=40 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Rabbits is \\begin{array}{rcl} 53-20=33. \\end{array} There are a total of 25 Ducks and Goats on a farm. Given that the total number of legs on the farm is 68, find the number of Goats **A** 5 **B** 14 **C** 9 **D** 11 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 25\\times2=50 \\end{array} legs. However, there are actually 68 legs. Therefore, there are \\begin{array}{rcl} 68-50=18 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Ducks is \\begin{array}{rcl} 25-9=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 25\\times4=100 \\end{array} legs. However, there are actually only 68 legs. Therefore, there are a shortage of \\begin{array}{rcl} 100-68=32 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 25-16=9. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_17) 9 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 25\\times2=50 \\end{array} legs. However, there are actually 68 legs. Therefore, there are \\begin{array}{rcl} 68-50=18 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Ducks is \\begin{array}{rcl} 25-9=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 25\\times4=100 \\end{array} legs. However, there are actually only 68 legs. Therefore, there are a shortage of \\begin{array}{rcl} 100-68=32 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 25-16=9. \\end{array} There are a total of 115 Gooses and Horses on a farm. Given that the total number of legs on the farm is 260, find the number of Gooses **A** 96 **B** 102 **C** 108 **D** 100 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 115\\times2=230 \\end{array} legs. However, there are actually 260 legs. Therefore, there are \\begin{array}{rcl} 260-230=30 \\end{array} extra legs. If we replace one Goose by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 30\\div2=15. \\end{array} The number of Gooses is \\begin{array}{rcl} 115-15=100. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 115\\times4=460 \\end{array} legs. However, there are actually only 260 legs. Therefore, there are a shortage of \\begin{array}{rcl} 460-260=200 \\end{array} legs. If we replace one Horse by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 200\\div2=100. \\end{array} The number of Horses is \\begin{array}{rcl} 115-100=15. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_18) 100 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 115\\times2=230 \\end{array} legs. However, there are actually 260 legs. Therefore, there are \\begin{array}{rcl} 260-230=30 \\end{array} extra legs. If we replace one Goose by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 30\\div2=15. \\end{array} The number of Gooses is \\begin{array}{rcl} 115-15=100. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 115\\times4=460 \\end{array} legs. However, there are actually only 260 legs. Therefore, there are a shortage of \\begin{array}{rcl} 460-260=200 \\end{array} legs. If we replace one Horse by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 200\\div2=100. \\end{array} The number of Horses is \\begin{array}{rcl} 115-100=15. \\end{array} There are a total of 73 Chickens and Cows on a farm. Given that the total number of legs on the farm is 148, find the number of Chickens **A** 68 **B** 73 **C** 77 **D** 72 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 73\\times2=146 \\end{array} legs. However, there are actually 148 legs. Therefore, there are \\begin{array}{rcl} 148-146=2 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Chickens is \\begin{array}{rcl} 73-1=72. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 73\\times4=292 \\end{array} legs. However, there are actually only 148 legs. Therefore, there are a shortage of \\begin{array}{rcl} 292-148=144 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 144\\div2=72. \\end{array} The number of Cows is \\begin{array}{rcl} 73-72=1. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_19) 72 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 73\\times2=146 \\end{array} legs. However, there are actually 148 legs. Therefore, there are \\begin{array}{rcl} 148-146=2 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Chickens is \\begin{array}{rcl} 73-1=72. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 73\\times4=292 \\end{array} legs. However, there are actually only 148 legs. Therefore, there are a shortage of \\begin{array}{rcl} 292-148=144 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 144\\div2=72. \\end{array} The number of Cows is \\begin{array}{rcl} 73-72=1. \\end{array} There are a total of 46 Ducks and Horses on a farm. Given that the total number of legs on the farm is 116, find the number of Horses **A** 15 **B** 12 **C** 9 **D** 20 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 46\\times2=92 \\end{array} legs. However, there are actually 116 legs. Therefore, there are \\begin{array}{rcl} 116-92=24 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Ducks is \\begin{array}{rcl} 46-12=34. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 46\\times4=184 \\end{array} legs. However, there are actually only 116 legs. Therefore, there are a shortage of \\begin{array}{rcl} 184-116=68 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Horses is \\begin{array}{rcl} 46-34=12. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_20) 12 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 46\\times2=92 \\end{array} legs. However, there are actually 116 legs. Therefore, there are \\begin{array}{rcl} 116-92=24 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Ducks is \\begin{array}{rcl} 46-12=34. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 46\\times4=184 \\end{array} legs. However, there are actually only 116 legs. Therefore, there are a shortage of \\begin{array}{rcl} 184-116=68 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Horses is \\begin{array}{rcl} 46-34=12. \\end{array} There are a total of 45 Chickens and Rabbits on a farm. Given that the total number of legs on the farm is 92, find the number of Rabbits **A** 9 **B** 1 **C** \-4 **D** \-2 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 45\\times2=90 \\end{array} legs. However, there are actually 92 legs. Therefore, there are \\begin{array}{rcl} 92-90=2 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Chickens is \\begin{array}{rcl} 45-1=44. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 45\\times4=180 \\end{array} legs. However, there are actually only 92 legs. Therefore, there are a shortage of \\begin{array}{rcl} 180-92=88 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Rabbits is \\begin{array}{rcl} 45-44=1. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_21) 1 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 45\\times2=90 \\end{array} legs. However, there are actually 92 legs. Therefore, there are \\begin{array}{rcl} 92-90=2 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Chickens is \\begin{array}{rcl} 45-1=44. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 45\\times4=180 \\end{array} legs. However, there are actually only 92 legs. Therefore, there are a shortage of \\begin{array}{rcl} 180-92=88 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Rabbits is \\begin{array}{rcl} 45-44=1. \\end{array} There are a total of 84 Chickens and Pigs on a farm. Given that the total number of legs on the farm is 240, find the number of Chickens **A** 49 **B** 53 **C** 56 **D** 48 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 84\\times2=168 \\end{array} legs. However, there are actually 240 legs. Therefore, there are \\begin{array}{rcl} 240-168=72 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 72\\div2=36. \\end{array} The number of Chickens is \\begin{array}{rcl} 84-36=48. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 84\\times4=336 \\end{array} legs. However, there are actually only 240 legs. Therefore, there are a shortage of \\begin{array}{rcl} 336-240=96 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 96\\div2=48. \\end{array} The number of Pigs is \\begin{array}{rcl} 84-48=36. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_22) 48 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 84\\times2=168 \\end{array} legs. However, there are actually 240 legs. Therefore, there are \\begin{array}{rcl} 240-168=72 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 72\\div2=36. \\end{array} The number of Chickens is \\begin{array}{rcl} 84-36=48. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 84\\times4=336 \\end{array} legs. However, there are actually only 240 legs. Therefore, there are a shortage of \\begin{array}{rcl} 336-240=96 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 96\\div2=48. \\end{array} The number of Pigs is \\begin{array}{rcl} 84-48=36. \\end{array} There are a total of 73 Gooses and Pigs on a farm. Given that the total number of legs on the farm is 156, find the number of Pigs **A** 3 **B** 9 **C** 2 **D** 5 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 73\\times2=146 \\end{array} legs. However, there are actually 156 legs. Therefore, there are \\begin{array}{rcl} 156-146=10 \\end{array} extra legs. If we replace one Goose by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 10\\div2=5. \\end{array} The number of Gooses is \\begin{array}{rcl} 73-5=68. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 73\\times4=292 \\end{array} legs. However, there are actually only 156 legs. Therefore, there are a shortage of \\begin{array}{rcl} 292-156=136 \\end{array} legs. If we replace one Pig by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 136\\div2=68. \\end{array} The number of Pigs is \\begin{array}{rcl} 73-68=5. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_23) 5 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 73\\times2=146 \\end{array} legs. However, there are actually 156 legs. Therefore, there are \\begin{array}{rcl} 156-146=10 \\end{array} extra legs. If we replace one Goose by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 10\\div2=5. \\end{array} The number of Gooses is \\begin{array}{rcl} 73-5=68. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 73\\times4=292 \\end{array} legs. However, there are actually only 156 legs. Therefore, there are a shortage of \\begin{array}{rcl} 292-156=136 \\end{array} legs. If we replace one Pig by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 136\\div2=68. \\end{array} The number of Pigs is \\begin{array}{rcl} 73-68=5. \\end{array} There are a total of 102 Ducks and Cows on a farm. Given that the total number of legs on the farm is 268, find the number of Ducks **A** 71 **B** 66 **C** 70 **D** 65 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 102\\times2=204 \\end{array} legs. However, there are actually 268 legs. Therefore, there are \\begin{array}{rcl} 268-204=64 \\end{array} extra legs. If we replace one Duck by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Ducks is \\begin{array}{rcl} 102-32=70. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 102\\times4=408 \\end{array} legs. However, there are actually only 268 legs. Therefore, there are a shortage of \\begin{array}{rcl} 408-268=140 \\end{array} legs. If we replace one Cow by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 140\\div2=70. \\end{array} The number of Cows is \\begin{array}{rcl} 102-70=32. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_24) 70 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 102\\times2=204 \\end{array} legs. However, there are actually 268 legs. Therefore, there are \\begin{array}{rcl} 268-204=64 \\end{array} extra legs. If we replace one Duck by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Ducks is \\begin{array}{rcl} 102-32=70. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 102\\times4=408 \\end{array} legs. However, there are actually only 268 legs. Therefore, there are a shortage of \\begin{array}{rcl} 408-268=140 \\end{array} legs. If we replace one Cow by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 140\\div2=70. \\end{array} The number of Cows is \\begin{array}{rcl} 102-70=32. \\end{array} There are a total of 34 Gooses and Dogs on a farm. Given that the total number of legs on the farm is 96, find the number of Gooses **A** 22 **B** 28 **C** 20 **D** 16 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 34\\times2=68 \\end{array} legs. However, there are actually 96 legs. Therefore, there are \\begin{array}{rcl} 96-68=28 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 28\\div2=14. \\end{array} The number of Gooses is \\begin{array}{rcl} 34-14=20. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 34\\times4=136 \\end{array} legs. However, there are actually only 96 legs. Therefore, there are a shortage of \\begin{array}{rcl} 136-96=40 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Dogs is \\begin{array}{rcl} 34-20=14. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_25) 20 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 34\\times2=68 \\end{array} legs. However, there are actually 96 legs. Therefore, there are \\begin{array}{rcl} 96-68=28 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 28\\div2=14. \\end{array} The number of Gooses is \\begin{array}{rcl} 34-14=20. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 34\\times4=136 \\end{array} legs. However, there are actually only 96 legs. Therefore, there are a shortage of \\begin{array}{rcl} 136-96=40 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Dogs is \\begin{array}{rcl} 34-20=14. \\end{array} There are a total of 53 Gooses and Donkeys on a farm. Given that the total number of legs on the farm is 204, find the number of Gooses **A** 7 **B** 6 **C** 5 **D** 4 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 53\\times2=106 \\end{array} legs. However, there are actually 204 legs. Therefore, there are \\begin{array}{rcl} 204-106=98 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 98\\div2=49. \\end{array} The number of Gooses is \\begin{array}{rcl} 53-49=4. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 53\\times4=212 \\end{array} legs. However, there are actually only 204 legs. Therefore, there are a shortage of \\begin{array}{rcl} 212-204=8 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Donkeys is \\begin{array}{rcl} 53-4=49. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_26) 4 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 53\\times2=106 \\end{array} legs. However, there are actually 204 legs. Therefore, there are \\begin{array}{rcl} 204-106=98 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 98\\div2=49. \\end{array} The number of Gooses is \\begin{array}{rcl} 53-49=4. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 53\\times4=212 \\end{array} legs. However, there are actually only 204 legs. Therefore, there are a shortage of \\begin{array}{rcl} 212-204=8 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Donkeys is \\begin{array}{rcl} 53-4=49. \\end{array} There are a total of 19 Ducks and Horses on a farm. Given that the total number of legs on the farm is 60, find the number of Horses **A** 11 **B** 19 **C** 8 **D** 15 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 19\\times2=38 \\end{array} legs. However, there are actually 60 legs. Therefore, there are \\begin{array}{rcl} 60-38=22 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 22\\div2=11. \\end{array} The number of Ducks is \\begin{array}{rcl} 19-11=8. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 19\\times4=76 \\end{array} legs. However, there are actually only 60 legs. Therefore, there are a shortage of \\begin{array}{rcl} 76-60=16 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Horses is \\begin{array}{rcl} 19-8=11. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_27) 11 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 19\\times2=38 \\end{array} legs. However, there are actually 60 legs. Therefore, there are \\begin{array}{rcl} 60-38=22 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 22\\div2=11. \\end{array} The number of Ducks is \\begin{array}{rcl} 19-11=8. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 19\\times4=76 \\end{array} legs. However, there are actually only 60 legs. Therefore, there are a shortage of \\begin{array}{rcl} 76-60=16 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Horses is \\begin{array}{rcl} 19-8=11. \\end{array} There are a total of 38 Chickens and Rabbits on a farm. Given that the total number of legs on the farm is 128, find the number of Chickens **A** 12 **B** 15 **C** 16 **D** 10 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 38\\times2=76 \\end{array} legs. However, there are actually 128 legs. Therefore, there are \\begin{array}{rcl} 128-76=52 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Chickens is \\begin{array}{rcl} 38-26=12. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 38\\times4=152 \\end{array} legs. However, there are actually only 128 legs. Therefore, there are a shortage of \\begin{array}{rcl} 152-128=24 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Rabbits is \\begin{array}{rcl} 38-12=26. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_28) 12 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 38\\times2=76 \\end{array} legs. However, there are actually 128 legs. Therefore, there are \\begin{array}{rcl} 128-76=52 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Chickens is \\begin{array}{rcl} 38-26=12. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 38\\times4=152 \\end{array} legs. However, there are actually only 128 legs. Therefore, there are a shortage of \\begin{array}{rcl} 152-128=24 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Rabbits is \\begin{array}{rcl} 38-12=26. \\end{array} There are a total of 116 Chickens and Donkeys on a farm. Given that the total number of legs on the farm is 280, find the number of Chickens **A** 98 **B** 90 **C** 94 **D** 92 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 116\\times2=232 \\end{array} legs. However, there are actually 280 legs. Therefore, there are \\begin{array}{rcl} 280-232=48 \\end{array} extra legs. If we replace one Chicken by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 48\\div2=24. \\end{array} The number of Chickens is \\begin{array}{rcl} 116-24=92. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 116\\times4=464 \\end{array} legs. However, there are actually only 280 legs. Therefore, there are a shortage of \\begin{array}{rcl} 464-280=184 \\end{array} legs. If we replace one Donkey by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 184\\div2=92. \\end{array} The number of Donkeys is \\begin{array}{rcl} 116-92=24. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_29) 92 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 116\\times2=232 \\end{array} legs. However, there are actually 280 legs. Therefore, there are \\begin{array}{rcl} 280-232=48 \\end{array} extra legs. If we replace one Chicken by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 48\\div2=24. \\end{array} The number of Chickens is \\begin{array}{rcl} 116-24=92. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 116\\times4=464 \\end{array} legs. However, there are actually only 280 legs. Therefore, there are a shortage of \\begin{array}{rcl} 464-280=184 \\end{array} legs. If we replace one Donkey by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 184\\div2=92. \\end{array} The number of Donkeys is \\begin{array}{rcl} 116-92=24. \\end{array} There are a total of 61 Gooses and Goats on a farm. Given that the total number of legs on the farm is 124, find the number of Gooses **A** 66 **B** 57 **C** 60 **D** 56 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 61\\times2=122 \\end{array} legs. However, there are actually 124 legs. Therefore, there are \\begin{array}{rcl} 124-122=2 \\end{array} extra legs. If we replace one Goose by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Gooses is \\begin{array}{rcl} 61-1=60. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 61\\times4=244 \\end{array} legs. However, there are actually only 124 legs. Therefore, there are a shortage of \\begin{array}{rcl} 244-124=120 \\end{array} legs. If we replace one Goat by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 120\\div2=60. \\end{array} The number of Goats is \\begin{array}{rcl} 61-60=1. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_30) 60 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 61\\times2=122 \\end{array} legs. However, there are actually 124 legs. Therefore, there are \\begin{array}{rcl} 124-122=2 \\end{array} extra legs. If we replace one Goose by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 2\\div2=1. \\end{array} The number of Gooses is \\begin{array}{rcl} 61-1=60. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 61\\times4=244 \\end{array} legs. However, there are actually only 124 legs. Therefore, there are a shortage of \\begin{array}{rcl} 244-124=120 \\end{array} legs. If we replace one Goat by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 120\\div2=60. \\end{array} The number of Goats is \\begin{array}{rcl} 61-60=1. \\end{array} There are a total of 56 Ducks and Goats on a farm. Given that the total number of legs on the farm is 180, find the number of Goats **A** 42 **B** 31 **C** 34 **D** 40 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 56\\times2=112 \\end{array} legs. However, there are actually 180 legs. Therefore, there are \\begin{array}{rcl} 180-112=68 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Ducks is \\begin{array}{rcl} 56-34=22. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 56\\times4=224 \\end{array} legs. However, there are actually only 180 legs. Therefore, there are a shortage of \\begin{array}{rcl} 224-180=44 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 44\\div2=22. \\end{array} The number of Goats is \\begin{array}{rcl} 56-22=34. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_31) 34 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 56\\times2=112 \\end{array} legs. However, there are actually 180 legs. Therefore, there are \\begin{array}{rcl} 180-112=68 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 68\\div2=34. \\end{array} The number of Ducks is \\begin{array}{rcl} 56-34=22. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 56\\times4=224 \\end{array} legs. However, there are actually only 180 legs. Therefore, there are a shortage of \\begin{array}{rcl} 224-180=44 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 44\\div2=22. \\end{array} The number of Goats is \\begin{array}{rcl} 56-22=34. \\end{array} There are a total of 123 Gooses and Donkeys on a farm. Given that the total number of legs on the farm is 264, find the number of Gooses **A** 113 **B** 114 **C** 118 **D** 122 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 123\\times2=246 \\end{array} legs. However, there are actually 264 legs. Therefore, there are \\begin{array}{rcl} 264-246=18 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Gooses is \\begin{array}{rcl} 123-9=114. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 123\\times4=492 \\end{array} legs. However, there are actually only 264 legs. Therefore, there are a shortage of \\begin{array}{rcl} 492-264=228 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 228\\div2=114. \\end{array} The number of Donkeys is \\begin{array}{rcl} 123-114=9. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_32) 114 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 123\\times2=246 \\end{array} legs. However, there are actually 264 legs. Therefore, there are \\begin{array}{rcl} 264-246=18 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Gooses is \\begin{array}{rcl} 123-9=114. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 123\\times4=492 \\end{array} legs. However, there are actually only 264 legs. Therefore, there are a shortage of \\begin{array}{rcl} 492-264=228 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 228\\div2=114. \\end{array} The number of Donkeys is \\begin{array}{rcl} 123-114=9. \\end{array} There are a total of 74 Chickens and Goats on a farm. Given that the total number of legs on the farm is 208, find the number of Chickens **A** 44 **B** 43 **C** 50 **D** 40 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 74\\times2=148 \\end{array} legs. However, there are actually 208 legs. Therefore, there are \\begin{array}{rcl} 208-148=60 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 60\\div2=30. \\end{array} The number of Chickens is \\begin{array}{rcl} 74-30=44. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 74\\times4=296 \\end{array} legs. However, there are actually only 208 legs. Therefore, there are a shortage of \\begin{array}{rcl} 296-208=88 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Goats is \\begin{array}{rcl} 74-44=30. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_33) 44 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 74\\times2=148 \\end{array} legs. However, there are actually 208 legs. Therefore, there are \\begin{array}{rcl} 208-148=60 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 60\\div2=30. \\end{array} The number of Chickens is \\begin{array}{rcl} 74-30=44. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 74\\times4=296 \\end{array} legs. However, there are actually only 208 legs. Therefore, there are a shortage of \\begin{array}{rcl} 296-208=88 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Goats is \\begin{array}{rcl} 74-44=30. \\end{array} There are a total of 95 Chickens and Goats on a farm. Given that the total number of legs on the farm is 244, find the number of Goats **A** 27 **B** 32 **C** 22 **D** 30 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 95\\times2=190 \\end{array} legs. However, there are actually 244 legs. Therefore, there are \\begin{array}{rcl} 244-190=54 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 54\\div2=27. \\end{array} The number of Chickens is \\begin{array}{rcl} 95-27=68. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 95\\times4=380 \\end{array} legs. However, there are actually only 244 legs. Therefore, there are a shortage of \\begin{array}{rcl} 380-244=136 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 136\\div2=68. \\end{array} The number of Goats is \\begin{array}{rcl} 95-68=27. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_34) 27 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 95\\times2=190 \\end{array} legs. However, there are actually 244 legs. Therefore, there are \\begin{array}{rcl} 244-190=54 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 54\\div2=27. \\end{array} The number of Chickens is \\begin{array}{rcl} 95-27=68. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 95\\times4=380 \\end{array} legs. However, there are actually only 244 legs. Therefore, there are a shortage of \\begin{array}{rcl} 380-244=136 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 136\\div2=68. \\end{array} The number of Goats is \\begin{array}{rcl} 95-68=27. \\end{array} There are a total of 37 Ducks and Rabbits on a farm. Given that the total number of legs on the farm is 132, find the number of Rabbits **A** 29 **B** 28 **C** 35 **D** 32 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 37\\times2=74 \\end{array} legs. However, there are actually 132 legs. Therefore, there are \\begin{array}{rcl} 132-74=58 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 58\\div2=29. \\end{array} The number of Ducks is \\begin{array}{rcl} 37-29=8. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 37\\times4=148 \\end{array} legs. However, there are actually only 132 legs. Therefore, there are a shortage of \\begin{array}{rcl} 148-132=16 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Rabbits is \\begin{array}{rcl} 37-8=29. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_35) 29 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 37\\times2=74 \\end{array} legs. However, there are actually 132 legs. Therefore, there are \\begin{array}{rcl} 132-74=58 \\end{array} extra legs. If we replace one Duck by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 58\\div2=29. \\end{array} The number of Ducks is \\begin{array}{rcl} 37-29=8. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 37\\times4=148 \\end{array} legs. However, there are actually only 132 legs. Therefore, there are a shortage of \\begin{array}{rcl} 148-132=16 \\end{array} legs. If we replace one Rabbit by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Rabbits is \\begin{array}{rcl} 37-8=29. \\end{array} There are a total of 42 Chickens and Horses on a farm. Given that the total number of legs on the farm is 104, find the number of Horses **A** 13 **B** 15 **C** 11 **D** 10 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 42\\times2=84 \\end{array} legs. However, there are actually 104 legs. Therefore, there are \\begin{array}{rcl} 104-84=20 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 20\\div2=10. \\end{array} The number of Chickens is \\begin{array}{rcl} 42-10=32. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 42\\times4=168 \\end{array} legs. However, there are actually only 104 legs. Therefore, there are a shortage of \\begin{array}{rcl} 168-104=64 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Horses is \\begin{array}{rcl} 42-32=10. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_36) 10 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 42\\times2=84 \\end{array} legs. However, there are actually 104 legs. Therefore, there are \\begin{array}{rcl} 104-84=20 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 20\\div2=10. \\end{array} The number of Chickens is \\begin{array}{rcl} 42-10=32. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 42\\times4=168 \\end{array} legs. However, there are actually only 104 legs. Therefore, there are a shortage of \\begin{array}{rcl} 168-104=64 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 64\\div2=32. \\end{array} The number of Horses is \\begin{array}{rcl} 42-32=10. \\end{array} There are a total of 71 Gooses and Dogs on a farm. Given that the total number of legs on the farm is 236, find the number of Gooses **A** 25 **B** 32 **C** 24 **D** 21 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 71\\times2=142 \\end{array} legs. However, there are actually 236 legs. Therefore, there are \\begin{array}{rcl} 236-142=94 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 94\\div2=47. \\end{array} The number of Gooses is \\begin{array}{rcl} 71-47=24. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 71\\times4=284 \\end{array} legs. However, there are actually only 236 legs. Therefore, there are a shortage of \\begin{array}{rcl} 284-236=48 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 48\\div2=24. \\end{array} The number of Dogs is \\begin{array}{rcl} 71-24=47. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_37) 24 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 71\\times2=142 \\end{array} legs. However, there are actually 236 legs. Therefore, there are \\begin{array}{rcl} 236-142=94 \\end{array} extra legs. If we replace one Goose by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 94\\div2=47. \\end{array} The number of Gooses is \\begin{array}{rcl} 71-47=24. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 71\\times4=284 \\end{array} legs. However, there are actually only 236 legs. Therefore, there are a shortage of \\begin{array}{rcl} 284-236=48 \\end{array} legs. If we replace one Dog by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 48\\div2=24. \\end{array} The number of Dogs is \\begin{array}{rcl} 71-24=47. \\end{array} There are a total of 59 Ducks and Horses on a farm. Given that the total number of legs on the farm is 232, find the number of Horses **A** 57 **B** 52 **C** 54 **D** 61 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 59\\times2=118 \\end{array} legs. However, there are actually 232 legs. Therefore, there are \\begin{array}{rcl} 232-118=114 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 114\\div2=57. \\end{array} The number of Ducks is \\begin{array}{rcl} 59-57=2. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 59\\times4=236 \\end{array} legs. However, there are actually only 232 legs. Therefore, there are a shortage of \\begin{array}{rcl} 236-232=4 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 4\\div2=2. \\end{array} The number of Horses is \\begin{array}{rcl} 59-2=57. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_38) 57 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 59\\times2=118 \\end{array} legs. However, there are actually 232 legs. Therefore, there are \\begin{array}{rcl} 232-118=114 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 114\\div2=57. \\end{array} The number of Ducks is \\begin{array}{rcl} 59-57=2. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 59\\times4=236 \\end{array} legs. However, there are actually only 232 legs. Therefore, there are a shortage of \\begin{array}{rcl} 236-232=4 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 4\\div2=2. \\end{array} The number of Horses is \\begin{array}{rcl} 59-2=57. \\end{array} There are a total of 48 Chickens and Dogs on a farm. Given that the total number of legs on the farm is 168, find the number of Dogs **A** 41 **B** 36 **C** 37 **D** 34 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 48\\times2=96 \\end{array} legs. However, there are actually 168 legs. Therefore, there are \\begin{array}{rcl} 168-96=72 \\end{array} extra legs. If we replace one Chicken by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 72\\div2=36. \\end{array} The number of Chickens is \\begin{array}{rcl} 48-36=12. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 48\\times4=192 \\end{array} legs. However, there are actually only 168 legs. Therefore, there are a shortage of \\begin{array}{rcl} 192-168=24 \\end{array} legs. If we replace one Dog by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Dogs is \\begin{array}{rcl} 48-12=36. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_39) 36 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 48\\times2=96 \\end{array} legs. However, there are actually 168 legs. Therefore, there are \\begin{array}{rcl} 168-96=72 \\end{array} extra legs. If we replace one Chicken by one Dog, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Dogs is \\begin{array}{rcl} 72\\div2=36. \\end{array} The number of Chickens is \\begin{array}{rcl} 48-36=12. \\end{array}**Method 2: Method of Assumption** Assume all were Dogs, there would be only \\begin{array}{rcl} 48\\times4=192 \\end{array} legs. However, there are actually only 168 legs. Therefore, there are a shortage of \\begin{array}{rcl} 192-168=24 \\end{array} legs. If we replace one Dog by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Dogs is \\begin{array}{rcl} 48-12=36. \\end{array} There are a total of 77 Chickens and Rabbits on a farm. Given that the total number of legs on the farm is 224, find the number of Chickens **A** 46 **B** 43 **C** 47 **D** 42 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 77\\times2=154 \\end{array} legs. However, there are actually 224 legs. Therefore, there are \\begin{array}{rcl} 224-154=70 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 70\\div2=35. \\end{array} The number of Chickens is \\begin{array}{rcl} 77-35=42. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 77\\times4=308 \\end{array} legs. However, there are actually only 224 legs. Therefore, there are a shortage of \\begin{array}{rcl} 308-224=84 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 84\\div2=42. \\end{array} The number of Rabbits is \\begin{array}{rcl} 77-42=35. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_40) 42 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 77\\times2=154 \\end{array} legs. However, there are actually 224 legs. Therefore, there are \\begin{array}{rcl} 224-154=70 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 70\\div2=35. \\end{array} The number of Chickens is \\begin{array}{rcl} 77-35=42. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 77\\times4=308 \\end{array} legs. However, there are actually only 224 legs. Therefore, there are a shortage of \\begin{array}{rcl} 308-224=84 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 84\\div2=42. \\end{array} The number of Rabbits is \\begin{array}{rcl} 77-42=35. \\end{array} There are a total of 62 Chickens and Cows on a farm. Given that the total number of legs on the farm is 160, find the number of Chickens **A** 44 **B** 40 **C** 52 **D** 46 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 62\\times2=124 \\end{array} legs. However, there are actually 160 legs. Therefore, there are \\begin{array}{rcl} 160-124=36 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 36\\div2=18. \\end{array} The number of Chickens is \\begin{array}{rcl} 62-18=44. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 62\\times4=248 \\end{array} legs. However, there are actually only 160 legs. Therefore, there are a shortage of \\begin{array}{rcl} 248-160=88 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Cows is \\begin{array}{rcl} 62-44=18. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_41) 44 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 62\\times2=124 \\end{array} legs. However, there are actually 160 legs. Therefore, there are \\begin{array}{rcl} 160-124=36 \\end{array} extra legs. If we replace one Chicken by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 36\\div2=18. \\end{array} The number of Chickens is \\begin{array}{rcl} 62-18=44. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 62\\times4=248 \\end{array} legs. However, there are actually only 160 legs. Therefore, there are a shortage of \\begin{array}{rcl} 248-160=88 \\end{array} legs. If we replace one Cow by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Cows is \\begin{array}{rcl} 62-44=18. \\end{array} There are a total of 56 Ducks and Donkeys on a farm. Given that the total number of legs on the farm is 192, find the number of Ducks **A** 16 **B** 18 **C** 20 **D** 15 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 56\\times2=112 \\end{array} legs. However, there are actually 192 legs. Therefore, there are \\begin{array}{rcl} 192-112=80 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 80\\div2=40. \\end{array} The number of Ducks is \\begin{array}{rcl} 56-40=16. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 56\\times4=224 \\end{array} legs. However, there are actually only 192 legs. Therefore, there are a shortage of \\begin{array}{rcl} 224-192=32 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Donkeys is \\begin{array}{rcl} 56-16=40. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_42) 16 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 56\\times2=112 \\end{array} legs. However, there are actually 192 legs. Therefore, there are \\begin{array}{rcl} 192-112=80 \\end{array} extra legs. If we replace one Duck by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 80\\div2=40. \\end{array} The number of Ducks is \\begin{array}{rcl} 56-40=16. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 56\\times4=224 \\end{array} legs. However, there are actually only 192 legs. Therefore, there are a shortage of \\begin{array}{rcl} 224-192=32 \\end{array} legs. If we replace one Donkey by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Donkeys is \\begin{array}{rcl} 56-16=40. \\end{array} There are a total of 76 Chickens and Donkeys on a farm. Given that the total number of legs on the farm is 164, find the number of Donkeys **A** 5 **B** 7 **C** 6 **D** 14 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 76\\times2=152 \\end{array} legs. However, there are actually 164 legs. Therefore, there are \\begin{array}{rcl} 164-152=12 \\end{array} extra legs. If we replace one Chicken by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Chickens is \\begin{array}{rcl} 76-6=70. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 76\\times4=304 \\end{array} legs. However, there are actually only 164 legs. Therefore, there are a shortage of \\begin{array}{rcl} 304-164=140 \\end{array} legs. If we replace one Donkey by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 140\\div2=70. \\end{array} The number of Donkeys is \\begin{array}{rcl} 76-70=6. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_43) 6 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 76\\times2=152 \\end{array} legs. However, there are actually 164 legs. Therefore, there are \\begin{array}{rcl} 164-152=12 \\end{array} extra legs. If we replace one Chicken by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Chickens is \\begin{array}{rcl} 76-6=70. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 76\\times4=304 \\end{array} legs. However, there are actually only 164 legs. Therefore, there are a shortage of \\begin{array}{rcl} 304-164=140 \\end{array} legs. If we replace one Donkey by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 140\\div2=70. \\end{array} The number of Donkeys is \\begin{array}{rcl} 76-70=6. \\end{array} There are a total of 60 Chickens and Goats on a farm. Given that the total number of legs on the farm is 136, find the number of Goats **A** 8 **B** 7 **C** 3 **D** 9 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 60\\times2=120 \\end{array} legs. However, there are actually 136 legs. Therefore, there are \\begin{array}{rcl} 136-120=16 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Chickens is \\begin{array}{rcl} 60-8=52. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 60\\times4=240 \\end{array} legs. However, there are actually only 136 legs. Therefore, there are a shortage of \\begin{array}{rcl} 240-136=104 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 104\\div2=52. \\end{array} The number of Goats is \\begin{array}{rcl} 60-52=8. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_44) 8 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 60\\times2=120 \\end{array} legs. However, there are actually 136 legs. Therefore, there are \\begin{array}{rcl} 136-120=16 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 16\\div2=8. \\end{array} The number of Chickens is \\begin{array}{rcl} 60-8=52. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 60\\times4=240 \\end{array} legs. However, there are actually only 136 legs. Therefore, there are a shortage of \\begin{array}{rcl} 240-136=104 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 104\\div2=52. \\end{array} The number of Goats is \\begin{array}{rcl} 60-52=8. \\end{array} There are a total of 94 Gooses and Donkeys on a farm. Given that the total number of legs on the farm is 200, find the number of Donkeys **A** 1 **B** 12 **C** 4 **D** 6 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 94\\times2=188 \\end{array} legs. However, there are actually 200 legs. Therefore, there are \\begin{array}{rcl} 200-188=12 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Gooses is \\begin{array}{rcl} 94-6=88. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 94\\times4=376 \\end{array} legs. However, there are actually only 200 legs. Therefore, there are a shortage of \\begin{array}{rcl} 376-200=176 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Donkeys is \\begin{array}{rcl} 94-88=6. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_45) 6 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 94\\times2=188 \\end{array} legs. However, there are actually 200 legs. Therefore, there are \\begin{array}{rcl} 200-188=12 \\end{array} extra legs. If we replace one Goose by one Donkey, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Donkeys is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Gooses is \\begin{array}{rcl} 94-6=88. \\end{array}**Method 2: Method of Assumption** Assume all were Donkeys, there would be only \\begin{array}{rcl} 94\\times4=376 \\end{array} legs. However, there are actually only 200 legs. Therefore, there are a shortage of \\begin{array}{rcl} 376-200=176 \\end{array} legs. If we replace one Donkey by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Donkeys is \\begin{array}{rcl} 94-88=6. \\end{array} There are a total of 36 Ducks and Goats on a farm. Given that the total number of legs on the farm is 112, find the number of Ducks **A** 13 **B** 21 **C** 16 **D** 19 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 36\\times2=72 \\end{array} legs. However, there are actually 112 legs. Therefore, there are \\begin{array}{rcl} 112-72=40 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Ducks is \\begin{array}{rcl} 36-20=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 36\\times4=144 \\end{array} legs. However, there are actually only 112 legs. Therefore, there are a shortage of \\begin{array}{rcl} 144-112=32 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 36-16=20. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_46) 16 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 36\\times2=72 \\end{array} legs. However, there are actually 112 legs. Therefore, there are \\begin{array}{rcl} 112-72=40 \\end{array} extra legs. If we replace one Duck by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 40\\div2=20. \\end{array} The number of Ducks is \\begin{array}{rcl} 36-20=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 36\\times4=144 \\end{array} legs. However, there are actually only 112 legs. Therefore, there are a shortage of \\begin{array}{rcl} 144-112=32 \\end{array} legs. If we replace one Goat by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 36-16=20. \\end{array} There are a total of 28 Chickens and Goats on a farm. Given that the total number of legs on the farm is 80, find the number of Chickens **A** 12 **B** 15 **C** 20 **D** 16 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 28\\times2=56 \\end{array} legs. However, there are actually 80 legs. Therefore, there are \\begin{array}{rcl} 80-56=24 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Chickens is \\begin{array}{rcl} 28-12=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 28\\times4=112 \\end{array} legs. However, there are actually only 80 legs. Therefore, there are a shortage of \\begin{array}{rcl} 112-80=32 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 28-16=12. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_47) 16 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 28\\times2=56 \\end{array} legs. However, there are actually 80 legs. Therefore, there are \\begin{array}{rcl} 80-56=24 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Chickens is \\begin{array}{rcl} 28-12=16. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 28\\times4=112 \\end{array} legs. However, there are actually only 80 legs. Therefore, there are a shortage of \\begin{array}{rcl} 112-80=32 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 32\\div2=16. \\end{array} The number of Goats is \\begin{array}{rcl} 28-16=12. \\end{array} There are a total of 57 Ducks and Horses on a farm. Given that the total number of legs on the farm is 120, find the number of Horses **A** 5 **B** 6 **C** 9 **D** 3 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 57\\times2=114 \\end{array} legs. However, there are actually 120 legs. Therefore, there are \\begin{array}{rcl} 120-114=6 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Ducks is \\begin{array}{rcl} 57-3=54. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 57\\times4=228 \\end{array} legs. However, there are actually only 120 legs. Therefore, there are a shortage of \\begin{array}{rcl} 228-120=108 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 108\\div2=54. \\end{array} The number of Horses is \\begin{array}{rcl} 57-54=3. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_48) 3 You are Right **Method 1: Method of Assumption** Assume all were Ducks, there would be only \\begin{array}{rcl} 57\\times2=114 \\end{array} legs. However, there are actually 120 legs. Therefore, there are \\begin{array}{rcl} 120-114=6 \\end{array} extra legs. If we replace one Duck by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 6\\div2=3. \\end{array} The number of Ducks is \\begin{array}{rcl} 57-3=54. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 57\\times4=228 \\end{array} legs. However, there are actually only 120 legs. Therefore, there are a shortage of \\begin{array}{rcl} 228-120=108 \\end{array} legs. If we replace one Horse by one Duck, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Ducks is \\begin{array}{rcl} 108\\div2=54. \\end{array} The number of Horses is \\begin{array}{rcl} 57-54=3. \\end{array} There are a total of 102 Chickens and Horses on a farm. Given that the total number of legs on the farm is 256, find the number of Chickens **A** 80 **B** 77 **C** 76 **D** 75 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 102\\times2=204 \\end{array} legs. However, there are actually 256 legs. Therefore, there are \\begin{array}{rcl} 256-204=52 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Chickens is \\begin{array}{rcl} 102-26=76. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 102\\times4=408 \\end{array} legs. However, there are actually only 256 legs. Therefore, there are a shortage of \\begin{array}{rcl} 408-256=152 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 152\\div2=76. \\end{array} The number of Horses is \\begin{array}{rcl} 102-76=26. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_49) 76 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 102\\times2=204 \\end{array} legs. However, there are actually 256 legs. Therefore, there are \\begin{array}{rcl} 256-204=52 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Chickens is \\begin{array}{rcl} 102-26=76. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 102\\times4=408 \\end{array} legs. However, there are actually only 256 legs. Therefore, there are a shortage of \\begin{array}{rcl} 408-256=152 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 152\\div2=76. \\end{array} The number of Horses is \\begin{array}{rcl} 102-76=26. \\end{array} There are a total of 27 Chickens and Rabbits on a farm. Given that the total number of legs on the farm is 84, find the number of Rabbits **A** 15 **B** 13 **C** 19 **D** 20 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 27\\times2=54 \\end{array} legs. However, there are actually 84 legs. Therefore, there are \\begin{array}{rcl} 84-54=30 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 30\\div2=15. \\end{array} The number of Chickens is \\begin{array}{rcl} 27-15=12. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 27\\times4=108 \\end{array} legs. However, there are actually only 84 legs. Therefore, there are a shortage of \\begin{array}{rcl} 108-84=24 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Rabbits is \\begin{array}{rcl} 27-12=15. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_50) 15 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 27\\times2=54 \\end{array} legs. However, there are actually 84 legs. Therefore, there are \\begin{array}{rcl} 84-54=30 \\end{array} extra legs. If we replace one Chicken by one Rabbit, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Rabbits is \\begin{array}{rcl} 30\\div2=15. \\end{array} The number of Chickens is \\begin{array}{rcl} 27-15=12. \\end{array}**Method 2: Method of Assumption** Assume all were Rabbits, there would be only \\begin{array}{rcl} 27\\times4=108 \\end{array} legs. However, there are actually only 84 legs. Therefore, there are a shortage of \\begin{array}{rcl} 108-84=24 \\end{array} legs. If we replace one Rabbit by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 24\\div2=12. \\end{array} The number of Rabbits is \\begin{array}{rcl} 27-12=15. \\end{array} There are a total of 99 Chickens and Horses on a farm. Given that the total number of legs on the farm is 220, find the number of Chickens **A** 91 **B** 96 **C** 88 **D** 85 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 99\\times2=198 \\end{array} legs. However, there are actually 220 legs. Therefore, there are \\begin{array}{rcl} 220-198=22 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 22\\div2=11. \\end{array} The number of Chickens is \\begin{array}{rcl} 99-11=88. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 99\\times4=396 \\end{array} legs. However, there are actually only 220 legs. Therefore, there are a shortage of \\begin{array}{rcl} 396-220=176 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Horses is \\begin{array}{rcl} 99-88=11. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_51) 88 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 99\\times2=198 \\end{array} legs. However, there are actually 220 legs. Therefore, there are \\begin{array}{rcl} 220-198=22 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 22\\div2=11. \\end{array} The number of Chickens is \\begin{array}{rcl} 99-11=88. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 99\\times4=396 \\end{array} legs. However, there are actually only 220 legs. Therefore, there are a shortage of \\begin{array}{rcl} 396-220=176 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Horses is \\begin{array}{rcl} 99-88=11. \\end{array} There are a total of 50 Chickens and Pigs on a farm. Given that the total number of legs on the farm is 188, find the number of Pigs **A** 44 **B** 42 **C** 43 **D** 45 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 50\\times2=100 \\end{array} legs. However, there are actually 188 legs. Therefore, there are \\begin{array}{rcl} 188-100=88 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Chickens is \\begin{array}{rcl} 50-44=6. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 50\\times4=200 \\end{array} legs. However, there are actually only 188 legs. Therefore, there are a shortage of \\begin{array}{rcl} 200-188=12 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Pigs is \\begin{array}{rcl} 50-6=44. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_52) 44 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 50\\times2=100 \\end{array} legs. However, there are actually 188 legs. Therefore, there are \\begin{array}{rcl} 188-100=88 \\end{array} extra legs. If we replace one Chicken by one Pig, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Pigs is \\begin{array}{rcl} 88\\div2=44. \\end{array} The number of Chickens is \\begin{array}{rcl} 50-44=6. \\end{array}**Method 2: Method of Assumption** Assume all were Pigs, there would be only \\begin{array}{rcl} 50\\times4=200 \\end{array} legs. However, there are actually only 188 legs. Therefore, there are a shortage of \\begin{array}{rcl} 200-188=12 \\end{array} legs. If we replace one Pig by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 12\\div2=6. \\end{array} The number of Pigs is \\begin{array}{rcl} 50-6=44. \\end{array} There are a total of 88 Chickens and Goats on a farm. Given that the total number of legs on the farm is 184, find the number of Chickens **A** 81 **B** 80 **C** 84 **D** 89 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 88\\times2=176 \\end{array} legs. However, there are actually 184 legs. Therefore, there are \\begin{array}{rcl} 184-176=8 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Chickens is \\begin{array}{rcl} 88-4=84. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 88\\times4=352 \\end{array} legs. However, there are actually only 184 legs. Therefore, there are a shortage of \\begin{array}{rcl} 352-184=168 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 168\\div2=84. \\end{array} The number of Goats is \\begin{array}{rcl} 88-84=4. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_53) 84 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 88\\times2=176 \\end{array} legs. However, there are actually 184 legs. Therefore, there are \\begin{array}{rcl} 184-176=8 \\end{array} extra legs. If we replace one Chicken by one Goat, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Goats is \\begin{array}{rcl} 8\\div2=4. \\end{array} The number of Chickens is \\begin{array}{rcl} 88-4=84. \\end{array}**Method 2: Method of Assumption** Assume all were Goats, there would be only \\begin{array}{rcl} 88\\times4=352 \\end{array} legs. However, there are actually only 184 legs. Therefore, there are a shortage of \\begin{array}{rcl} 352-184=168 \\end{array} legs. If we replace one Goat by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 168\\div2=84. \\end{array} The number of Goats is \\begin{array}{rcl} 88-84=4. \\end{array} There are a total of 82 Gooses and Cows on a farm. Given that the total number of legs on the farm is 216, find the number of Cows **A** 25 **B** 23 **C** 26 **D** 30 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 82\\times2=164 \\end{array} legs. However, there are actually 216 legs. Therefore, there are \\begin{array}{rcl} 216-164=52 \\end{array} extra legs. If we replace one Goose by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Gooses is \\begin{array}{rcl} 82-26=56. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 82\\times4=328 \\end{array} legs. However, there are actually only 216 legs. Therefore, there are a shortage of \\begin{array}{rcl} 328-216=112 \\end{array} legs. If we replace one Cow by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 112\\div2=56. \\end{array} The number of Cows is \\begin{array}{rcl} 82-56=26. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_54) 26 You are Right **Method 1: Method of Assumption** Assume all were Gooses, there would be only \\begin{array}{rcl} 82\\times2=164 \\end{array} legs. However, there are actually 216 legs. Therefore, there are \\begin{array}{rcl} 216-164=52 \\end{array} extra legs. If we replace one Goose by one Cow, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Cows is \\begin{array}{rcl} 52\\div2=26. \\end{array} The number of Gooses is \\begin{array}{rcl} 82-26=56. \\end{array}**Method 2: Method of Assumption** Assume all were Cows, there would be only \\begin{array}{rcl} 82\\times4=328 \\end{array} legs. However, there are actually only 216 legs. Therefore, there are a shortage of \\begin{array}{rcl} 328-216=112 \\end{array} legs. If we replace one Cow by one Goose, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Gooses is \\begin{array}{rcl} 112\\div2=56. \\end{array} The number of Cows is \\begin{array}{rcl} 82-56=26. \\end{array} There are a total of 97 Chickens and Horses on a farm. Given that the total number of legs on the farm is 212, find the number of Chickens **A** 93 **B** 86 **C** 88 **D** 96 Prev Submit Prev Next Sorry. Please check the correct answer below. **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 97\\times2=194 \\end{array} legs. However, there are actually 212 legs. Therefore, there are \\begin{array}{rcl} 212-194=18 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Chickens is \\begin{array}{rcl} 97-9=88. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 97\\times4=388 \\end{array} legs. However, there are actually only 212 legs. Therefore, there are a shortage of \\begin{array}{rcl} 388-212=176 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Horses is \\begin{array}{rcl} 97-88=9. \\end{array} #### [**View Correct Answer**](https://psle-math.com/student/test/chicken-and-rabbit-problem#collapse_55) 88 You are Right **Method 1: Method of Assumption** Assume all were Chickens, there would be only \\begin{array}{rcl} 97\\times2=194 \\end{array} legs. However, there are actually 212 legs. Therefore, there are \\begin{array}{rcl} 212-194=18 \\end{array} extra legs. If we replace one Chicken by one Horse, we will have \\begin{array}{rcl} 4-2=2 \\end{array} more legs. Therefore, the number of Horses is \\begin{array}{rcl} 18\\div2=9. \\end{array} The number of Chickens is \\begin{array}{rcl} 97-9=88. \\end{array}**Method 2: Method of Assumption** Assume all were Horses, there would be only \\begin{array}{rcl} 97\\times4=388 \\end{array} legs. However, there are actually only 212 legs. Therefore, there are a shortage of \\begin{array}{rcl} 388-212=176 \\end{array} legs. If we replace one Horse by one Chicken, we will have \\begin{array}{rcl} 4-2=2 \\end{array} less legs. Therefore, the number of Chickens is \\begin{array}{rcl} 176\\div2=88. \\end{array} The number of Horses is \\begin{array}{rcl} 97-88=9. \\end{array} x - [SIGN IN](https://psle-math.com/student/test/chicken-and-rabbit-problem#modal_signin) - [SIGN UP](https://psle-math.com/student/test/chicken-and-rabbit-problem#modal_signup) or sign up with one of these services Facebook Google [](https://psle-math.com/) PSLE-Math.com Start winning at math! Be part of Singapore PSLE Math community and Unleash the Your Maths Potential\! ## General - [About us](https://psle-math.com/aboutus) - [Contact us](https://psle-math.com/contactus) ## Contact Us 6631-9759 [\[email protected\]](https://psle-math.com/cdn-cgi/l/email-protection) https://psle-math.com 2026 © All Rights Reserved. [Privacy Policy](https://psle-math.com/privacy-policy) \| [Terms of Service](https://psle-math.com/terms-and-conditions) ### What subject area do you need help in? 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There are a total of 51 Chickens and Cows on a farm. Given that the total number of legs on the farm is 108, find the number of Chickens **A** 48 **B** 53 **C** 49 **D** 44