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| Meta Title | In the figure, the value of resistor R is (25 + I/2) ohms, |
| Meta Description | In the figure, the value of resistor R is (25 + I/2) ohms, where I is the current in amperes. The current I is _________ |
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| Boilerpipe Text | Electric circuits miscellaneous
Easy Questions
Moderate Questions
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Electric Circuits
Electric circuits miscellaneous
In the figure, the value of resistor R is (25 + I/2) ohms, where I is the current in amperes. The current I is _________
15
5
10
None of these
Correct Option:
C
R =
25 +
I
2
Now V = RI
∴ 300 = I
25 +
I
∴ R = 25 +
I
2
2
∴ 600 = 50 I + I
2
I = 10 A or – 60 A
I
2
+ 50 I – 600 = 0
∴ I = 10A
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[Electric circuits miscellaneous](https://interviewmania.com/electric-circuits/electric-circuits-miscellaneous/1/1)
1. In the figure, the value of resistor R is (25 + I/2) ohms, where I is the current in amperes. The current I is \_\_\_\_\_\_\_\_\_

1. 1. 15
2. 5
3. 10
4. None of these
##### Correct Option: C
| | | | | | |
|---|---|---|---|---|---|
| R = |  | 25 + | I |  | |
| 2 | | | | | |
Now V = RI
| | | | | | | | | | |
|---|---|---|---|---|---|---|---|---|---|
| \∴ 300 = I |  | 25 + | I |  |  | \∴ R = 25 + | I |  | |
| 2 | 2 | | | | | | | | |
\∴ 600 = 50 I + I2
I = 10 A or – 60 A
I2 + 50 I – 600 = 0
\∴ I = 10A
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| Readable Markdown | #### Electric circuits miscellaneous
[Easy Questions](https://interviewmania.com/electric-circuits/electric-circuits-miscellaneous/1/1)
[Moderate Questions](https://interviewmania.com/electric-circuits/electric-circuits-miscellaneous/2/1)
[Difficult Questions](https://interviewmania.com/electric-circuits/electric-circuits-miscellaneous/3/1)
#### Electric Circuits
[Electric circuits miscellaneous](https://interviewmania.com/electric-circuits/electric-circuits-miscellaneous/1/1)
1. In the figure, the value of resistor R is (25 + I/2) ohms, where I is the current in amperes. The current I is \_\_\_\_\_\_\_\_\_

1. 1. 15
2. 5
3. 10
4. None of these
##### Correct Option: C
| | | | | | |
|---|---|---|---|---|---|
| R = |  | 25 + | I |  | |
| 2 | | | | | |
Now V = RI
| | | | | | | | | | |
|---|---|---|---|---|---|---|---|---|---|
| \∴ 300 = I |  | 25 + | I |  |  | \∴ R = 25 + | I |  | |
| 2 | 2 | | | | | | | | |
\∴ 600 = 50 I + I2
I = 10 A or – 60 A
I2 + 50 I – 600 = 0
\∴ I = 10A
*** |
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